Burt has 986 paperback
1 answer:
You might be interested in
Answer:
Probability that the sample proportion will be greater than 0.5 is 0.8133.
Step-by-step explanation:
We are given that the a particular candidate for public office is in fact favored by p = 48% of all registered voters. A polling organization is about to take a simple random sample of voters and will use the sample proportion to estimate p.
Suppose that the polling organization takes a simple random sample of 500 voters.
<em>Let </em><em> = sample proportion</em>
The z-score probability distribution for sample proportion is given by;
Z = ~ N(0,1)
where, = sample proportion
p = population proportion = 48%
n = sample of voters = 500
The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.
So, probability that the sample proportion will be greater than 0.5 is given by = P( > 0.50)
P( > 0.50) = P(
<
) = P(Z < 0.89) = 0.8133
<em>Now, in the z table the P(Z </em><em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.89 in the z table which has an area of 0.8133.</em>
Therefore, probability that the sample proportion will be greater than 0.50 is 0.8133.
1) 4.55
2) Short hit
Step-by-step explanation:
1)
The table containing the score and the relative probability of each score is:
Score 3 4 5 6 7
Probability 0.15 0.40 0.25 0.15 0.05
Here we call
X = Miguel's score on the Water Hole
The expected value of a certain variable X is given by:
where
are all the possible values that the variable X can take
is the probability that
Therefore in this problem, the expected value of MIguel's score is given by:
2)
In this problem, we call:
X = Miguel's score on the Water Hole
Here we have that:
- If the long hit is successfull, the expected value of X is
- Instead, if the long hit fails, the expected value of X is
Here we also know that the probability of a successfull long hit is
Which means that the probabilty of an unsuccessfull long hit is
Therefore, the expected value of X if Miguel chooses the long hit approach is:
In part 1) of the problem, we saw that the expected value for the short hit was instead
Since the expected value for X is lower (=better) for the short hit approach, we can say that the short hit approach is better.