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Gnoma [55]
4 years ago
11

Brad says that the literal equation a = 3b + 4c - a is solved for a. Do you agree yes or no?

Mathematics
1 answer:
galina1969 [7]4 years ago
6 0

Answer:

No

Step-by-step explanation:

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Write an equation to solve the problem.
Mrrafil [7]
D=rtthe distances are not equal, but they add up to a total of 400 milesone bus goes 55mph times t so that is 55t (that represents the distance in one direction)the other bus goes 45 mph,so that is 45t (that represents the distance in the other direction)the total distance is 400, so the equation is distance one direction + distance the other direction = 400your equation is 55t + 45t = 400                         100t = 400                              t= 4 hoursso after 4 hours they will be 400 miles apart
7 0
3 years ago
Read 2 more answers
Pls help me with my math
givi [52]

Answer:

The definition for the given piecewise-defined function is:   \boxed{\displaystyle\sf\ Option\:D:\:\: f(x) = \begin{cases}\displaystyle\sf\ x + 2 & \sf\:{if\:\:x \leq -1} \\\displaystyle\sf\ 2x + 4 & \sf\:{if\:\:x > -1}\end{cases}}.

Step-by-step explanation:

<h3>General Concepts:</h3>
  • Piecewise-defined functions.
  • Interval notations.

<h3>What is a piecewise-defined function?</h3>

A piecewise-defined function represents specific rules over different intervals of the domain.  

<h3>Symbols used in expressing interval notations:</h3>

Open interval: This means that the endpoint is <em>not</em> included in the interval.

We can use the following symbols to indicate the <u>exclusion</u> of endpoints in the interval:

  • Left or right parenthesis, "(  )" (or both).
  • Greater than (>) or less than (<) symbols.
  • Open dot "\circ" is another way of expressing the exclusion of an endpoint in the graph of a piecewise-defined function.

Closed interval: This implies the inclusion of endpoints in the interval.

We can use the following symbols to indicate the <u>inclusion</u> of endpoints in the interval:

  • Open- or closed brackets (or both), "[  ]."
  • Greater than or equal to (≥) or less than or equal to (≤) symbols.
  • Closed circle or dot, "•" is another way of expressing the <em>inclusion</em> of the endpoint in the graph of a piecewise-defined function.  

<h2>Determine the appropriate function rule that defines different parts of the domain.  </h2>

The best way to determine which piecewise-defined function represents the graph is by observing the <u>endpoints</u> and <u>orientation</u> of both partial lines.

  • Open circle on (-1, 2):  The graph shows that one of the partial lines has an <em>excluded</em> endpoint of (-1, 2) extending towards the <u>right</u>. This implies that its domain values are defined when x > -1.
  • Closed circle on (-1, 1): The graph shows that one of the partial lines has an <em>included</em> endpoint of (-1, 1) extended towards the <u>left</u>. Hence,  its domain values are defined when x ≤ -1.

Based on our observations from the previous step, we can infer that x > -1 or x ≤ -1 apply to piecewise-defined functions A or D. However, only one of those two options represent the graph.

<h2>Solution:</h2><h3>a) Test option A:</h3>

    \boxed{\displaystyle\sf Option\:A)\:\:\:f(x) = \begin{cases}\displaystyle\sf\ 2x + 2 & \sf\:{if\:\:x \leq -1} \\\displaystyle\sf\ x + 4 & \sf\:{if\:\:x > -1}\end{cases}}

<h3>Piece 1: If x ≤ -1, then it is defined by f(x) = 2x + 2. </h3>

We must choose a domain value that falls within the interval of x ≤ -1 whose output is included is included in the graph of the partial line with a <u>closed dot</u>.

Substitute x = -2 into f(x) = 2x + 2:  

  • f(x) = 2x + 2
  • f(-2) = 2(-2) + 2
  • f(-2) = -4 + 2
  • f(-2) = -2  ⇒  <em>False statement</em>.

⇒ The output value of f(-2) = -2 is <u>not</u> included in the graph of the partial line whose endpoint is at (-1, 1).

<h3>Piece 2: If x > -1, then it is defined by f(x) = x + 4. </h3>

We must choose a domain value that falls within the interval of x > -1 whose output is included in the graph of the partial line with an <u>open dot</u>.

Substitute x = 0 into  f(x) = x + 4:

  • f(x) = x + 4
  • f(0) = (0) + 4
  • f(0) = 4  ⇒  <em>True statement</em>.

⇒ The output value of f(0) = 4 <u>is</u> included in the graph of the partial line whose endpoint is at (-1, 2).

Conclusion for Option A:

Option A is not the correct piecewise-defined function because one of the pieces, f(x) = 2x + 2, does not specify the interval (-∞, -1].

<h3>b) Test option D:</h3>

    \boxed{\displaystyle\sf Option\:D)\:\:\:f(x) = \begin{cases}\displaystyle\sf\ x + 2 & \sf\:{if\:\:x \leq -1} \\\displaystyle\sf\ 2x + 4 & \sf\:{if\:\:x > -1}\end{cases}}

<h3>Piece 1:  If x ≤ -1, then it is defined by f(x) = x + 2. </h3>

We must choose a domain value that falls within the interval of x ≤ -1 whose output is included is included in the graph of the partial line with a <u>closed dot</u>.

Substitute x = -2 into f(x) = x + 2:

  • f(x) = x + 2
  • f(-2) = (-2) + 2
  • f(-2) = 0  ⇒  <em>True statement</em>.

⇒ The output value of f(-2) = 0 <u>is</u> included the graph of the partial line whose endpoint is at (-1, 1).

<h3>Piece 2: If x > -1, then it is defined by f(x) = 2x + 4.</h3>

We must choose a domain value that falls within the interval of x > -1 whose output is included is included in the graph of the partial line with an <u>open dot</u>.

Substitute x = 0 into f(x) = 2x + 4:

  • f(x) = 2x + 4
  • f(0) = 2(0) + 4
  • f(0) = 0 + 4 = 0  ⇒  <em>True statement</em>.

⇒ The output value of f(0) = 4 <u>is</u> included in the graph of the partial line whose endpoint is at (-1, 2).  

<h2>Final Answer: </h2>

We can infer that the piecewise-defined function that represents the graph is:

\boxed{\displaystyle\sf\ Option\:D:\:\: f(x) = \begin{cases}\displaystyle\sf\ x + 2 & \sf\:{if\:\:x \leq -1} \\\displaystyle\sf\ 2x + 4 & \sf\:{if\:\:x > -1}\end{cases}}.

________________________________________

Learn more about piecewise-defined functions here:

brainly.com/question/26145479

8 0
2 years ago
*HELP ASAP*
k0ka [10]

Using unit concepts, it is found that:

  • a) Grams.
  • b) Grams.
  • c) Grams squared.
  • d) Grams squared.

-----------------------------

  • For a data-set, the standard deviation has the same unit as the data-set, both for the sample and the population.
  • The variance has the unit squared, both for the sample and the population.
  • For example, if the data-set is in metres, the standard deviation will be in metres while the variance will be in squared metres.

-----------------------------

In this question, the data-set is in grams.

  • The standard deviation, both for the sample and the population, in items a and b, will be in grams.
  • The variance, both for the sample and the population, in items c and d, will be in grams squared.

A similar problem is given at brainly.com/question/14524219

5 0
3 years ago
If 6 inches of decorative ribbon costs $3.25 ,how much does a yard cost?
Rzqust [24]
It would cost $19.50. hope that helped
4 0
4 years ago
Read 2 more answers
A 16-ounce bottle of orange juice says it contains 200 milligrams of vitamin C, which is 250% of the daily recommended allowance
iren2701 [21]

Answer:

100% of the daily recommended allowance of vitamin C for adults is 80 milligrams.

Step-by-step explanation:

A 16-ounce bottle of orange juice says it contains 200 milligrams of vitamin C, which is 250% of the daily recommended allowance of vitamin C for adults.

100% will have = \frac{200}{250}\times100 = 80 milligrams

Hence, 100% of the daily recommended allowance of vitamin C for adults is 80 milligrams.

8 0
3 years ago
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