Question

A 0.023 kg beetle is sitting on a record player 0.15 m from the center of the record. If it takes 0.070 N of force to keep the beetle moving in a circle on the record, what is the tangential speed of the beetle?

Answer 1

Tangential speed= 0.68 m/s

Answer 2

Answer:

0.68 m/s

Explanation:

The centripetal force that keeps the beetle moving in circle is given by:

$F=m\frac{v^2}{r}$

where

m is the mass of the beetle

v is the tangential speed of the beetle

r is the distance of the beetle from the center of the record

In this problem, we know the force (F=0.070 N), the mass of the beetle (m=0.023 kg) and the distance from the center (r=0.15 m), therefore we can re-arrange the equation to find the tangential speed:

$v=\sqrt{\frac{Fr}{m}}=\sqrt{\frac{(0.070 N)(0.15 m)}{0.023 kg}}=0.68 m/s$