Answer:
The temperature rise of the water is = 0.14 °c
Explanation:
Height = 60 m
Potential energy change ΔP =
ΔP = m × 9.81 × 60
ΔP = (588.6 × m) Joule
Since the Potential energy change is equal to the internal energy change or Enthalpy change.
ΔP = ΔH
Since ΔH = m × C × ΔT
⇒ ΔP = m × C × ΔT
Put all the values in above formula we get
⇒ 588.6 × m = m × 4184 × ΔT
⇒ ΔT= 0.14 °c
Therefore the temperature rise of the water is = 0.14 °c
Answer: 1. .090km/h
2. I dont know
3. 1560
Explanation:
1. add all the numbers up and divide by 3 bc thats how many numbers there are.
2. I dont know
3. add all distances up
Answer:
E₄ = - 0.85 eV
E₂ = - 3.4 eV
Ephoton = 2.55 eV
Explanation:
The sum of Kinetic Energy (K) and Potential Energy (U) of the Helium atom is equal to the total energy of Helium atom in the specified state N. From Bohr's atomic model, the energy of a hydrogen atom in state N is given as:
En = K + U = (-1/n²)(13.6 eV)
a)
Here,
n = 4
Therefore,
E₄ = (-1/4²)(13.6 eV)
<u>E₄ = - 0.85 eV</u>
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b)
Here,
n = 2
Therefore,
E₂ = (-1/2²)(13.6 eV)
<u>E₂ = - 3.4 eV</u>
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c)
The energy of photon emitted in the transition from level 4 to level 2 will be equal to the difference in the energy of both levels:
Ephoton = ΔE = E₄ - E₂
Ephoton = - 0.85 eV - (- 3.4 eV)
<u>Ephoton = 2.55 eV</u>
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Newton first law state that anything in motion or rest will remain in motion or in rest until an external force is applied
Newton third law of motion state that every action have equal and opposite reaction
Answer:
8.0 seconds
Explanation:
Remember: at the highest point, the ball's velocity is 0.
Given:
Δy = 80 m
v = 0 m/s
a = -9.8 m/s²
Find: t
Δy = vt − ½ at²
(80 m) = (0 m/s) t − ½ (-9.8 m/s²) t²
t = 4.0 s
It takes 4.0 seconds for the ball to reach the highest point. So the ball spends a total of 8.0 seconds in the air.