A bond forming between aluminum and iodine would be of which type?

nikklg [1K]

To find the mole of a substance, you take the mass divided by the molar mass of that substance~

3 0

3 years ago

Propane (c3h8) is burned in oxygen to produce carbon dioxide and water. the heat of combustion of propane is -2012 kj/mole. how

Olegator [25]

$C_{3} H_{8} + 5 O_{2} ---\ \textgreater \ 3CO_{2} +4H_{2}O (-2012 \frac{kJ}{mol} )


3 mol 10 mol


C_{3}H_{8} is /excess /reactant

because 3 mol propane require 15 mol oxygen (by reaction)

5 mol oxygen ---1 mol propane, so

10 mol oxygen ---2 mol propane

Only 2 mole propane will be burned,

so 

2012 ( kJ/mol)*2 mol =4024 KJ heat will be given off

Correct answer is number 4.


$

5 0

3 years ago

How many grams are in 3 mol of KBr?

e-lub [12.9K]

Answer: 7

Explanation:

6 0

4 years ago

Read 2 more answers

which solution below would be considered the most acidic?a. 2.9 x 10-4 m hclb. 4.5 x 10-5 m hno3c. 1.0 x 10-7 m nacld. 1.5 x 10-

kkurt [141]

Answer:

a. 2,9x10⁻⁴ M HCl

Explanation:

A solution is considered acidic when its concentration of H⁺ is higher than 1x10⁻⁷. The higher concentration of H⁺ will be the most acidic solution.

a. 2,9x10⁻⁴ M HCl. In water, this solution dissolves as H⁺ and Cl⁻. That means concentration of H⁺ is 2,9x10⁻⁴ M.

b. 4,5x10⁻⁵M HNO₃. In the same way, concentration of H⁺ is 4,5x10⁻⁵M.

c. 1,0x10⁻⁷M NaCl. As this solution doesn't produce H⁺, the solution is not acidic

d. 1,5x10⁻²M KOH. This solution produce OH⁻. That means the solution is basic nor acidic.

Thus, the solution considered the most acidic is a. 2,9x10⁻⁴ M HCl, because has the higher concentration of H⁺.

I hope it helps!

7 0

3 years ago

A student has 100. mL of 0.400 M CuSO4(aq) and is asked to make 100. mL of 0.150 M CuSO4(aq) for a spectrophotometry experiment.

ValentinkaMS [17]

Answer:

a. 37.5 mL

b. See the description below

Explanation:

a. Volume of 0.400 M CuSO₄(aq) required for the preparation

In dissolutions, since the number of moles of solute is constant, the equation is:

$C_1\times V_1=C_2\times V_2$

Substitute and solve for V₁

$0.400M\times V_1=0.150M\times 100ml$

$V_1=0.150M\times 100.ml/0.400M=37.5ml$

b. Briefly describe the essential steps to most accurately prepare the 0.150 M CuSO₄(aq) from the 0.400 M CuSO₄(aq)

You will use the stock solution, the funnel, the buret, and distilled water.

i) Using the funnel, fill in the buret with with 50 ml of the stock solution, i.e. the 100. ml of 0.400 M CuSO₄(aq) solution.

ii) Pour 37.5 ml of the stock solution from the burete into the volumetric flask.

iii) Carefully add disitlled water to the 37.5ml of the stock solution in the volumetric flask until the mark (50 ml) on the volumetric flask.

iv) Put the stopper and rotate the volumetric flask to homegenize the solution.

3 0

4 years ago