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tresset_1 [31]
2 years ago
10

Write a word or phrase begining with each letter of the word CHANGE that describes changed you have observed in everyday objects

.
Chemistry
1 answer:
ipn [44]2 years ago
6 0
C – coming to senses and finally realized that everything is dynamic and I should learn to invest into knowing what of these changes are right or wrong and being

H – hopeful that someday, these changes will actually make sense and that all of these questions and confusions will be answered in the right time and the right place. But whatever happens, I must learn to

A – adapt from the different things I see everyday, If the world changes for its betterment or for its worse, then I too, should change as well to go with the flow. However, keep in mind to

N – never leave the small things behind because these things when summed up actually what make sense of everything and could possibly answer the

G – growing dynamics of the world and its inhabitants. Throughout all this, it is always important to
<span>
E-educate yourself, that when the change will finally take effect on you, you will be ready.</span>
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Sodium tripolyphosphate is used in detergents to make them effective in hard water. Calculate the oxidation number of phosphorus
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The answer for this question is A
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A reaction has activation energy of 85kjper mol. What is the effect on the rate of raising the temperature from 20degree to 30 d
DENIUS [597]

Answer: The rate increases 3 times on raising the temperature from 20degree to 30 degree​

Explanation:

According to Arrhenius equation with change in temperature, the formula is as follows.

ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]

where k_2 = rate constant at temp T_2

k_1 = rate constant at temp T_1

E_a= activation energy

R= gas constant

T_1= temperature = 20^0C=(20+273)K=293K

T_2= temperature = 30^0C=(30+273)K=303K

ln \frac{k_{2}}{k_{1}} = \frac{-85\times 1000J/mol}{8.314J/Kmol}[\frac{1}{303} - \frac{1}{293}]

ln \frac{k_{2}}{k_{1}}=1.15

\frac{k_{2}}{k_{1}}=3

Thus rate increases 3 times on raising the temperature from 20degree to 30 degree​

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Answer:

22.9 Liters CO(g) needed

Explanation:

2CO(g)     +   O₂(g)    =>    2CO₂(g)

? Liters          32.65g

                 = 32.65g/32g/mol

                 =   1.02 moles O₂

Rxn ratio for CO to O₂ = 2 mole CO(g) to 1 mole O₂(g)

∴moles CO(g) needed = 2 x 1.02 moles CO(g) = 2.04 moles CO(g)

Conditions of standard equation* is STP (0°C & 1atm) => 1 mole any gas occupies 22.4 Liters.

∴Volume of CO(g) = 1.02mole x 22.4Liters/mole = 22.9 Liters CO(g) needed

___________________

*Standard Equation => molecular rxn balanced to smallest whole number ratio coefficients is assumed to be at STP conditions (0°C & 1atm).

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