You can either use an ice table or the Henderson-Hasselbalch equation. I would use the Henderson-Hasselbalch equation since that is the easiest method to use in my opinion. The Henderson-Hasselbalch equation is pH=pKa+log([A⁻]/[HA]).
pKa=-log(Ka) (which equals 1.77 in this question)
[A⁻]=concentration of conjugate base (0.386M in this question)
[HA]=concentration of acid (0.451M in this question)
When you plug everything in you should get a pH of 1.697.
I hope this helps. Let me know if anything is unclear or you want me to explain anything in more detail.
Answer:The bigger the atom the lesser the ability of the atom to hold on to its valence electrons.
Explanation:
The larger the atom, the lesser the tendency for the atom to withhold its valence electrons.
The size of an atom is usually estimated in terms of its atomic radius. Across the period in the periodic table, the atomic radius decreases progressively from left to right. This is due to the progressive increase in the nuclear charge (i.e., the number of protons in the nucleus) without an attendant increase in the number of electron shells.
Similarly, down the group, the atomic radius increases progressively from top to bottom due to the successive number of electrons' shells.
Thus, the larger the atom's radius, the smaller the Ionization energy because of the increasing shielding effect of inner shell electrons on the electron to be removed from the nuclear attraction.
Finally, we can conclude that as the atom becomes larger, the tendency to withhold the electrons on the outer shell decreases due to distance and the shielding/ screening effect.
Answer:
Nandiyan yan sa binasa mo
In order to answer this question, the units of volume must be consistent. In this problem, we decide the unit m3 to be uniform. Option A is equal to 12 m3, option b is equal to 1.2x10^8/100^3 or 120 m3. Option C is 2.0 x10^4/ 10^3 or 20 m3. Option D is 1.2x10^8/ 1000^3 or 0.12 m3. The greatest volume is option b. 120 m3.