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adelina 88 [10]

3 years ago

8

Which gas law has assumptions of a fixed amount and temperature of a gas

1 answer:

romanna [79]3 years ago

4 0

The answer is Boyle's law. Boyle's law states that the volume of a fixed mass of a gas is inversely proportional to its pressure at a constant absolute temperature.
That is; V α 1/P , at constant temperature and a fixed amount of the gas.
Such that V= k/P where k is a constant

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Who is the father of genetics

-BARSIC- [3]

Gregor Mendel

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6 0

3 years ago

Read 2 more answers

A certain flexible weather balloon contains 7.4 L of helium gas. Initially, the balloon is in WP at 8500ft, where the temperatur

Free_Kalibri [48]

<h2>The new volume of the balloon at the top of Pikes Peak is 10.2 L</h2>

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 577.0 torr

$P_2$ = final pressure of gas = 400 torr

$V_1$ = initial volume of gas = 7.4 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $20.6^oC=273+20.6=293.6K$

$T_2$ = final temperature of gas = $7.5^oC=273+7.5=280.5K$

Now put all the given values in the above equation, we get:

$\frac{577.0\times 7.4}{293.6K}=\frac{400.0\times V_2}{280.5K}$

$V_2=10.2L$

Thus the new volume of the balloon at the top of Pikes Peak is 10.2 L

Learn more about combined gas law

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3 0

3 years ago

Aluminum boils at 2467°C. Aluminum’s boiling point in Kelvin is 2194.<br> T or F

dusya [7]

That is false because aluminum melts at 2,470C

7 0

3 years ago

What mass of a 0.583 molar solution of iron(III) nitrate is needed to obtain a) 0.0200 moles of iron(III) nitrate, b) 0.0500 mol

geniusboy [140]

Answer:

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Explanation:

34rg

8 0

3 years ago

0.415 g of an unknown triprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an

Arturiano [62]

Answer:

Explanation:

Initial burette reading = 1.81 mL

final burette reading = 39.7 mL

volume of NaOH used = 39.7 - 1.81 = 37.89 mL .

37.89 mL of .1029 M NaOH is used to neutralise triprotic acid

No of moles contained by 37.89 mL of .1029 M NaOH

= .03789 x .1029 moles

= 3.89 x 10⁻³ moles

Since acid is triprotic , its equivalent weight = molecular weight / 3

No of moles of triprotic acid = 3.89 x 10⁻³ / 3

= 1.30 x 10⁻³ moles .

8 0

3 years ago