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adelina 88 [10]

3 years ago

8

Which gas law has assumptions of a fixed amount and temperature of a gas

1 answer:

romanna [79]3 years ago

4 0

The answer is Boyle's law. Boyle's law states that the volume of a fixed mass of a gas is inversely proportional to its pressure at a constant absolute temperature.
That is; V α 1/P , at constant temperature and a fixed amount of the gas.
Such that V= k/P where k is a constant

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enyata [817]

Answer:

b)5l x 10kg c)10kg + 9l (Not sure for the last 1)

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3 years ago

Ionic bonding occurs when ______ atom donates one or more _______ to a _______ atom

Svetllana [295]

Answer:

ionic bonding occurs when unstable atoms donates one or more valence electrons to a unstable atom

Explanation:

7 0

2 years ago

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Igoryamba

Atomic mass is the answer!!
Explanation: An elements atomic number won’t be able to change

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2 years ago

A laboratory analysis of a sample finds it is composed of 38.8% carbon, 16.2% hydrogen, and 45.1% nitrogen. What is its empirica

Sladkaya [172]

Answer: The empirical formula for the given compound is $CH_5N$

Explanation : Given,

Percentage of C = 38.8 %

Percentage of H = 16.2 %

Percentage of N = 45.1 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 38.8 g

Mass of H = 16.2 g

Mass of N = 45.4 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{38.8g}{12g/mole}=3.23moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{16.2g}{1g/mole}=16.2moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{45.4g}{14g/mole}=3.24moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.

For Carbon = $\frac{3.23}{3.23}=1$

For Hydrogen = $\frac{16.2}{3.23}=5.01\approx 5$

For Oxygen = $\frac{3.24}{3.23}=1.00\approx 1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 1 : 5 : 1

Hence, the empirical formula for the given compound is $C_1H_5N_1=CH_5N$

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3 years ago

An aqueous solution containing 35.5 g of an unknown molecular (non-electrolyte) compound in 151.0 g of water was found to have a

Tasya [4]

ccccccccccccccccccccccccccccccccccc

8 0

3 years ago