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2 years ago

Someone please help me dont scroll i need help

Chemistry

1 answer:

Diano4ka-milaya [45]2 years ago

8 0

A line that stay s straight across the graph

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What are the limitations of the Klmn electronic configuration style of writing

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In the KLMN electronic configuration style of writing K denotes the first shell which can hold up to two electrons, L denotes the second shell which can hold up to eight (2 + 6) or 8 electrons, M denotes the third shell which can hold up to eight (2 + 6 + 10) or 18 electrons etc.

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3 years ago

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A cylinder of iron has a mass of 23.45 g. If it is placed on an electronic balance that reports all masses 18.00% too low due to

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4 years ago

Calculate the molecular weight of a dibasic acid.0.56gm of which is required 250ml of N/20 sodium hydroxide solution for neutral

Alekssandra [29.7K]

<u>Answer: </u>The molecular weight of the dibasic acid is 89.6 g/mol

<u>Explanation:</u>

Normality is defined as the amount of solute expressed in the number of gram equivalents present per liter of solution. The units of normality are eq/L. The formula used to calculate normality:

$\text{Normality}=\frac{\text{Given mass of solute}\times 1000}{\text{Equivalent mass of solute}\times \text{Volume of solution (mL)}}$ ....(1)

We are given:

Normality of solution = $\frac{1}{20}=0.05N$

Given mass of solute = 0.56 g

Volume of solution = 250 mL

Putting values in equation 1, we get:

$0.05=\frac{0.56\times 1000}{\text{Equivalent mass of solute}\times 250}\\\\\text{Equivalent mass of solute}=\frac{0.56\times 1000}{0.05\times 250}=44.8g/eq$

Equivalent weight of an acid is calculated by using the equation:

$\text{Equivalent weight}=\frac{\text{Molar mass}}{\text{Basicity}}$ .....(2)

Equivalent weight of acid = 44.8 g/eq

Basicity of an acid = 2 eq/mol

Putting values in equation 2, we get:

$44.8g/eq=\frac{\text{Molar mass}}{2eq/mol}\\\\\text{Molar mass}=(44.8g/eq\times 2eq/mol)=89.6g/mol$

Hence, the molecular weight of the dibasic acid is 89.6 g/mol

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3 years ago