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Katena32 [7]
3 years ago
7

A certain flexible weather balloon contains 7.4 L of helium gas. Initially, the balloon is in WP at 8500ft, where the temperatur

e is 20.6oC and the barometric pressure is 577.0 torr. The balloon then is taken to the top of Pike’s Peak at an altitude of 14,100ft, where the pressure is 400 torr and the temperature is 7.5oC. What is the new volume of the balloon at the top of Pikes Peak?
Chemistry
1 answer:
Free_Kalibri [48]3 years ago
3 0
<h2>The new volume of the balloon at the top of Pikes Peak is 10.2 L</h2>

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 577.0 torr

P_2 = final pressure of gas = 400 torr

V_1 = initial volume of gas = 7.4 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 20.6^oC=273+20.6=293.6K

T_2 = final temperature of gas = 7.5^oC=273+7.5=280.5K

Now put all the given values in the above equation, we get:

\frac{577.0\times 7.4}{293.6K}=\frac{400.0\times V_2}{280.5K}

V_2=10.2L

Thus the new volume of the balloon at the top of Pikes Peak is 10.2 L

Learn more about combined gas law

brainly.com/question/12089296

brainly.com/question/4133756

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The decomposition of carbon disulfide to carbon monosulfide and sulfur is first order with k=2.8 ×10^-7 at 1000°C .What is the h
RoseWind [281]

Answer:

2.5×10⁶ s

Explanation:

From the question given above, the following data were obtained:

Rate constant (K) = 2.8×10¯⁷ s¯¹

Half-life (t½) =?

The half-life of a first order reaction is given by:

Half-life (t½) = 0.693 / Rate constant (K)

t½ = 0.693 / K

With the above formula, we can obtain the half-life of the reaction as follow:

Rate constant (K) = 2.8×10¯⁷ s¯¹

Half-life (t½) =?

t½ = 0.693 / K

t½ = 0.693 / 2.8×10¯⁷

t½ = 2.5×10⁶ s

Therefore, the half-life of the reaction is 2.5×10⁶ s

6 0
2 years ago
A 41.1 g sample of solid CO2 (dry ice) is added to a container at a temperature of 100 K with a volume of 3.4 L.A. If the contai
marta [7]

Answer:

Approximately 6.81 × 10⁵ Pa.

Assumption: carbon dioxide behaves like an ideal gas.

Explanation:

Look up the relative atomic mass of carbon and oxygen on a modern periodic table:

  • C: 12.011;
  • O: 15.999.

Calculate the molar mass of carbon dioxide \rm CO_2:

M\!\left(\mathrm{CO_2}\right) = 12.011 + 2\times 15.999 = 44.009\; \rm g \cdot mol^{-1}.

Find the number of moles of molecules in that 41.1\;\rm g sample of \rm CO_2:

n = \dfrac{m}{M} = \dfrac{41.1}{44.009} \approx 0.933900\; \rm mol.

If carbon dioxide behaves like an ideal gas, it should satisfy the ideal gas equation when it is inside a container:

P \cdot V = n \cdot R \cdot T,

where

  • P is the pressure inside the container.
  • V is the volume of the container.
  • n is the number of moles of particles (molecules, or atoms in case of noble gases) in the gas.
  • R is the ideal gas constant.
  • T is the absolute temperature of the gas.

Rearrange the equation to find an expression for P, the pressure inside the container.

\displaystyle P = \frac{n \cdot R \cdot T}{V}.

Look up the ideal gas constant in the appropriate units.

R = 8.314 \times 10^3\; \rm L \cdot Pa \cdot K^{-1} \cdot mol^{-1}.

Evaluate the expression for P:

\begin{aligned} P &=\rm \frac{0.933900\; mol \times 8.314 \times 10^3 \; L \cdot Pa \cdot K^{-1} \cdot mol^{-1} \times 298\; K}{3.4\; L} \cr &\approx \rm 6.81\times 10^5\; Pa \end{aligned}.

Apply dimensional analysis to verify the unit of pressure.

4 0
3 years ago
0.200 grams of HCl is dissolved in 0.801 grams water. The density of the solution formed is 1.10 g/mL. What is the molarity of t
alina1380 [7]

Answer:

M=6.03M

Explanation:

Hello,

In this case, since the molarity is computed by:

M=\frac{n_{solute}}{V_{solution}}

Whereas the solute is the hydrochloric acid, we compute the corresponding moles with its molar mass (36.45 g/mol):

n_{solute}=0.200gHCl*\frac{1molHCl}{36.45gHCl} =0.00549molHCl

Next, since the solution contains both HCl and water, we compute the volume in liters by using its density:

V_{solution}=(0.200+0.801)g*\frac{1mL}{1.10g} *\frac{1L}{1000mL} =9.1x10^{-4}L

Therefore, the molarity turns out:

M=\frac{0.00549mol}{9.1x10^{-4}L}\\ \\M=6.03M

Regards.

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3 years ago
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<h2>YOUR ANSWER Is number of istopes</h2>

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Can someone help me?
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Answer:

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