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masya89 [10]
3 years ago
8

Solve the equation

Mathematics
1 answer:
zalisa [80]3 years ago
6 0
Simplify the fraction on the left
  3(x -3) = 3(2x -3)
Divide by 3
  x -3 = 2x -3
Subtract the left side
  0 = (2x -3) -(x -3)
  0 = x

The solution is x = 0.
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LA plane is trying to travel 250 miles at a bearing of 20° E of S, however, it ends 230 miles away from the
Semmy [17]

Answer:

The wind pushed the plane 65.01 miles in the direction of 45.56 ^{\circ} East of North  with respect to the destination point.

Step-by-step explanation:

Let origin, O, br the starting point and point D be the destination at 250 miles at a bearing of 20° E of S, but due to wind let D' be the actual position of the plane at 230 miles away from the  starting point in the direction of 35° E of South as shown in the figure.

So, we have |OD|=250 miles and |OD'|=230 miles.

Vector \overrightarrow{DD'} is the displacement vector of the plane pushed by the wind.

From figure, the magnitude of the required displacement vector is

|DD'|=\sqrt{|AB|^2+|PQ|^2}\;\cdots(i)

and the direction is \alpha east of north as shown in the figure,

\tan \alpha=\frac{|PQ|}{|AB|}\;\cdots(ii)

From the figure,

|AB|=|OA-OB|

\Rightarrow |AB|=|OD\cos 20 ^{\circ}-OD'\cos 35 ^{\circ}|

\Rightarrow |AB|=|250\cos 20 ^{\circ}-230\cos 35 ^{\circ}|

\Rightarrow |AB|=45.52 miles

Again, |PQ|=|OP-OQ|

\Rightarrow |PQ|=|OD\sin 20 ^{\circ}-OD'\sin 35 ^{\circ}|

\Rightarrow |PQ|=|250\sin 20 ^{\circ}-230\sin 35 ^{\circ}|

\Rightarrow |PQ|=46.42 miles

Now, from equations (i) and (ii), we have

|DD'|=\sqrt{|45.52|^2+|46.42|^2}=65.01 miles, and

\tan \alpha=\frac{|46.42|}{|45.52|}

\alpha=\tan^{-1}\left(\frac{|46.42|}{|45.52|}\right)=45.56 ^{\circ}

Hence, the wind pushed the plane 65.01 miles in the direction of 45.56 ^{\circ} E astof North  with respect to the destination point.

5 0
3 years ago
What is the effect on the figure k > 1 show your work please thankssss
skad [1K]
2, 3, 5, 1000 any number that is larger than 1.
4 0
3 years ago
Read 2 more answers
Complete the recursive formula of the arithmetic sequence -3, -1, 1, 3,...
Strike441 [17]

Given:

The given arithmetic sequence is:

-3,-1,1,3,...

To find:

The recursive formula of the given arithmetic sequence.

Solution:

We have,

-3,-1,1,3,...

Here, the first term is -3. So, b(1)=-3.

The common difference is:

d=-1-(-3)

d=-1+3

d=2

The recursive formula of an arithmetic sequence is:

b(n)=b(n-1)+d

Where, d is the common difference.

Putting d=2, we get

b(n)=b(n-1)+2

Therefore, the recursive formula of the given arithmetic sequence is b(n)=b(n-1)+2, where b(1)=-3.

8 0
3 years ago
Find the missing coordinate to complete the ordered pair.
MA_775_DIABLO [31]
(9,-4) you have to plugin 9 to the equation in the form of x. Then you add 5 and that would be your y value
8 0
3 years ago
Help i’m doing my exam
jolli1 [7]
Dude I don’t think using this for an exam is it but ok
5 0
3 years ago
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