Answer:
The volume of the water after it freezes (at 0°C) is 354.4 mL.
Explanation:
We need to use this additional information, the densities of liquid water and ice at 0 °C are 1.000 g/mL and 0.917 g/mL, respectively.
Step 1. Find the mass of water before it freezes.
Step 2. The mass does not change when the temperature does. So, you take the grams of water and divide it by the density of the ice to obtain the volume it occupies.
32 h this is because this problem
This is an incomplete question, here is a complete question.
The reaction below has a Kp value of 3.3 × 10⁻⁵. What is the value of Kc for this reaction at 700 K?
Answer : The value of is,
Explanation :
The relation between and is:
where,
= equilibrium constant at constant pressure =
R = gas constant = 0.0821 L.atm/mol.K
T = temperature = 700 K
= change in number of gaseous moles = Product moles - Reactant moles = (2+1) - (2) = 3 - 1 = 1 mol
= equilibrium constant
Now put all the given values in the above expression, we get:
Therefore, the value of is,
2 H2 + O2 = 2 H2O
1 mole O2 --------------- 2 moles H2O
13.35 moles O2 -------- ( moles H2O)
moles H2O = 13.35 x 2 / 1
<span>= </span>26.7 moles of H2O
<span>hope this helps!</span>