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vovikov84 [41]
3 years ago
13

What is the percent by mass of oxygen in carbon dioxide (CO2)?

Chemistry
2 answers:
krok68 [10]3 years ago
8 0

Answer:

I think that it will be

Explanation:

72.71%

vesna_86 [32]3 years ago
5 0

Answer:

72.71%

Explanation:

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Why do farmers spray water over their crops before a frost?
Nezavi [6.7K]

Answer:

When water freezes and turns into ice, it releases latent heat. Then, the ice that builds up on the plant will insulate it from the colder surrounding air temperatures. Because of this, some growers choose to spray their crop with water before the freeze occurs.

Explanation:

5 0
3 years ago
For this assignment, the target compound that you should synthesize is 1-methyl-4-nitro-benzene. This is an electrophilic aromat
Liono4ka [1.6K]

Answer:

The methyl group will already be present  

Explanation:

You want to make 1-methyl-4-nitrobenzene.

The question is, "Do I start with the methyl group on the ring and then nitrate, or do I start with the nitro group on the ring and then add the methyl group?"

The methyl group is activating and ortho, para directing.

The nitro group is deactivating and meta directing.

You want a para-substituted product, so you choose to nitrate toluene, as in the reaction scheme below.

 

5 0
4 years ago
At 35.0°C and 3.00 atm pressure, a gas has a volume of 1.40 L. What pressure does the gas have at 0.00°C and a volume of 0.950 L
Luba_88 [7]

The answer to your question is

A. P2=P1V1T2/T1V2

Trust me I am learning this stuff in class and I got everything memorized

I hope this helps

May I have brainliest I am working on my ranks! :)

7 0
3 years ago
Read 2 more answers
How many grams of water are produced when 2.50 g of aluminum hydroxide are used?
Bess [88]

Answer:

13

Explanation:

6 0
3 years ago
Iodine-131, t1/2 = 8.0 days, is used in the diagnosis and treatment of thyroid gland diseases. If a laboratory sample of iodine-
SashulF [63]

Answer:

32,0 days.

Explanation:

The radioactive decay follows:

N_{t} = N_{0}e^{\frac{-0.693t}{t_{1/2}}

Where Nt is the concentration in a time t (6,22x10¹⁷), N₀ is the initial concentration (9,95x10¹⁸) Half life time is 8,0 days and t is the time it take to drop this concentration. Replacing:

6.22x10^{17} = 9,95x10^{18}e^{\frac{-0.693t}{8 days}

0,0625 = e^{\frac{-0.693t}{8days}

ln 0,0625 = {\frac{-0.693t}{8days}

-2,77*8days = -0.693t

-22,2days = -0.693t

32,0days = t

It take <em>32,0 days</em>

<em></em>

I hope it helps!

7 0
3 years ago
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