Answer: 2/15
Explanation: 2/9 x 3/5 then simplify it
Answer:
Therefore 200.96 ft.of fencing are needed to go around the pool path.
Step-by-step explanation:
Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.
The radius of the outside edge the pool path is
= Radius of the pool + The width of the path
= (28+4) ft
= 32 ft.
To find the length of fencing, we need to find the circumference of outside the pool path.
Here r= 32 ft
The circumference of outside edge of the pool path
=

=200.96 ft.
Therefore 200.96 ft.of fencing are needed to go around the pool path.
Answer:
Area of rectangle = 225/2 or 112.5
Step-by-step explanation:
Given,
Consider a rectangle ABCD.
Let AC be a diagonal of rectangle of length = 15
In triangle ABC.
Sin 45° =height/hypotenuse {SinФ = height / hypotenuse}
Here, hypotenuse = diagonal of rectangle ( i.e AC = 15)
And height is AB
Therefore, sin 45° = AB/AC
or sin 45° = AB / 15
or 1/√2 = AB /15
AB = 15/√2
Similarly we can find Base (i.e BC) using cosine.
Cos 45° = Base/Hypotenuse
Cos 45° = BC / AC
or 1/√2 = BC/15
BC = 15/√2
Hence we got length of rectangle , AB= 15/√2
And width of rectangle , BC = 15/√2
Therefore, area of rectangle = Length × Width
Area of rectangle = 15/√2 × 15/√2 = 225/2
Hence, area of rectangle = 225/2 = 112.5
Answer:
I don't get the "number of 40" part, but here's my best shot!
3(40x)-5
Step-by-step explanation:
Answer: 2 and 3
Step-by-step explanation:
I did this and got it right