1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Likurg_2 [28]
3 years ago
13

I will definitely rate 5 stars/brainliest!!! HELP PLEASE!!! State University must purchase 1,100 computers from three vendors. V

endor 1 charges $500 per computer plus a delivery charge of $5,000. Vendor 2 charges $350 per computer plus a delivery charge of $4,000. Vendor 3 charges $250 per computer plus a delivery charge of $6,000. Vendor 1 will sell the university at most 500 computers; vendor 2, at most 900; and vendor 3, at most 400. Formulate an IP to minimize the cost of purchasing the needed computers (Please solve the LP with Lindo or Excel).
Engineering
1 answer:
romanna [79]3 years ago
3 0
Why 1+12+ Y3 < 1100
Says the state of university Need to purchase 1100 computers in total, we have the following answer on the way top
You might be interested in
If the compound swivel base is set on 60 degrees at the lathe centerline index, how many degrees will the reading be at the cros
Effectus [21]

Answer:

C.30°

Explanation:

Given that compound swivel base is set on 60° at the lathe center line index.

We need to find reading on cross slide index

We know that relationship between center line index and cross slide index in angle 2∝=β

Where ∝ Angle of swivel and β is the reading on cross line index.

So by using above  relationship between center line index and cross slide index  

2∝=60°⇒∝=30°

So our option is C.

6 0
4 years ago
Resistors of 150 Ω and 100 Ω are connected in parallel. What is their equivalent resistance?
aliina [53]
<h3>your question : </h3>

Resistors of 150 Ω and 100 Ω are connected in parallel. What is their equivalent resistance?

Answer:

the equivalent resistance will be 60 ohms

Explanation:

see the solution in attached picture

6 0
3 years ago
What is the magnitude of the maximum stress that exists at the tip of an internal crack having a radius of curvature of 2.5×10-4
krok68 [10]

Answer:

1788.9 MPa

Explanation:

The magnitude of the maximum stress (σ) can be calculated usign the following equation:

\sigma = 2\sigma_{0} \sqrt{\frac{a}{\rho}}

<u>Where:</u>

<em>ρ: is the radius of curvature = 2.5x10⁻⁴ mm (0.9843x10⁻⁵ in)</em>

<em>σ₀: is the tensile stress = 100x10⁶ Pa (14500 psi) </em>

<em>2a: is the crack length = 4x10⁻² mm (1.575x10⁻³ in) </em>

Hence, the  maximum stress (σ) is:

\sigma = 2*100\cdot 10^{6} Pa \sqrt{\frac{(4 \cdot 10^{-2} mm)/2}{2.5 \cdot 10^{-4} mm}} = 1.79 \cdot 10^{6} Pa = 1788.9 MPa    

Therefore, the magnitude of the maximum stress is 1788.9 MPa.

I hope it helps you!

5 0
4 years ago
Based on the ELR, the stability classification of the atmosphere at the airport between the surface and 3000 m is
Anna11 [10]

Answer:

The answer is "conditionally unstable"

Explanation:

The conditional volatility is really a condition of uncertainty, which reflects on whether increasing air is polluted or not. It determines the rate of ambient delay, which has been between humid and dry adiabatic rates. In general, the environment is in an unilaterally unhealthy region.

Classification dependent on ELR:

Larger than 10 \frac{^{\circ}C}{1000} m Around 10 and 6 \frac{^{\circ}C}{1000} m or less 6 \frac{^{\circ}C}{1000} m volatile implicitly unreliable Therefore ELR is implicitly unreliable 9 \frac{^{\circ}C}{1000} m, that's why it is "conditionally unstable".

6 0
4 years ago
You are using a Geiger counter to measure the activity of a radioactive substance over the course of several minutes. If the rea
Reika [66]

Answer: 33.35 minutes

Explanation:

A(t) = A(o) *(.5)^[t/(t1/2)]....equ1

Where

A(t) = geiger count after time t = 100

A(o) = initial geiger count = 400

(t1/2) = the half life of decay

t = time between geiger count = 66.7 minutes

Sub into equ 1

100=400(.5)^[66.7/(t1/2)

Equ becomes

.25= (.5)^[66.7/(t1/2)]

Take log of both sides

Log 0.25 = [66.7/(t1/2)] * log 0.5

66.7/(t1/2) = 2

(t1/2) = (66.7/2 ) = 33.35 minutes

4 0
3 years ago
Other questions:
  • An engineering drawing shows the: (A) dimensions, tolerances, cost, and sales or use volume of a component.(B) dimensions, toler
    10·1 answer
  • Rubber bands provided the thrust to get your rocket going. Why did the rocket keep moving after it left the launch pad and the r
    5·1 answer
  • Describe the operation of a pneumatic robot controlled by a drum
    10·1 answer
  • A 200 Ω transmission line is to be matched to a computer terminal with ZL = (50 − j25) Ω by inserting an appropriate reactance i
    10·1 answer
  • The value of universal gas constant is same for all gases?<br> a) yes<br> b)No
    15·1 answer
  • What affect results when there is an impact between earth and is astroids check all that apply.
    12·1 answer
  • Give three examples of how engineering has made human life better in your opinion.
    13·1 answer
  • A solid circular cylinder of mass m, radius r, and length l is pivoted about a transverse axis
    12·1 answer
  • What plane is this? and when was it made?
    11·1 answer
  • Calculate area moment of inertia for a circular cross section with 6 mm diameter
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!