Answer:
(a) E = 0 N/C
(b) E = 0 N/C
(c) E = 7.78 x10^5 N/C
Explanation:
We are given a hollow sphere with following parameters:
Q = total charge on its surface = 23.6 μC = 23.6 x 10^-6 C
R = radius of sphere = 26.1 cm = 0.261 m
Permittivity of free space = ε0 = 8.85419 X 10−12 C²/Nm²
The formula for the electric field intensity is:
E = (1/4πεo)(Q/r²)
where, r = the distance from center of sphere where the intensity is to be found.
(a)
At the center of the sphere r = 0. Also, there is no charge inside the sphere to produce an electric field. Thus the electric field at center is zero.
<u>E = 0 N/C</u>
(b)
Since, the distance R/2 from center lies inside the sphere. Therefore, the intensity at that point will be zero, due to absence of charge inside the sphere (q = 0 C).
<u>E = 0 N/C</u>
(c)
Since, the distance of 52.2 cm is outside the circle. So, now we use the formula to calculate the Electric Field:
E = (1/4πεo)[(23.6 x 10^-6 C)/(0.522m)²]
<u>E = 7.78 x10^5 N/C</u>
Answer:
Um...
Explanation:
This is what I like to see teachers giving out.
The resulting output voltage (rms) when a 50 mV rms input applied is -187.5 mV.
<h3>What is rms voltage?</h3>
Root Mean Square Voltage is the amount of AC power which produces the same heating effect as DC Power would have produced.
Vo = -gm x Vi (Rd II Rl )
Vo = -5000 x 10⁻⁶ x 50 x 10⁻³ x (1.5k II 1.5k )
Vo = -25 x 10⁻² x 750 x 10⁻³
Vo = -187.5 mV
Hence, resulting output voltage (rms) when a 50 mV rms input applied is -187.5 mV.
Learn more about rms voltage.
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Box A , because box A has a greater mass in the same volume
