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Aleonysh [2.5K]
3 years ago
6

Which of the following is true about the sequence graphed below?

Mathematics
2 answers:
Semenov [28]3 years ago
8 0

Answer with explanation:

When you will look, at the points in the coordinate plane, (2,9), (3, 7.5), (4,6), (5,4.5), (6,3), (7,1.5), (8,0), they lie along a straight line, because

  Slope between two points

  =\frac{9-7.5}{2-3}=\frac{7.5-6}{3-4}=\frac{4.5 -3}{5-6}=\frac{3-1.5}{6-7}=\frac{1.5-0}{7-8}\\\\=-1.5

So,all the points lie in a line.

y(0)=8

y(1.5)=7

y(3)=6

y(4.5)=5

y(6)=4

y(7.5)=3

y(9)=2

Now ,difference between two consecutive terms = 7-8=6-7=5-6=4-5=3-4=2-3=-1

So,→ Sequence is Arithmetic, because the terms have a common Difference.

Option A

Liula [17]3 years ago
3 0
A, because it declines at a steady ratw
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patriot [66]

Answer:

yes, it is a right triangle and ∡Q is the right angle

Step-by-step explanation:

if the slope of QR is the opposite reciprocal of QS then the two segments are perpendicular and form a 90° angle

slope of QR:  -3 - (-1) ÷ 2 - 0  = -2 ÷ 2 = -1

slope of QS:  -3 - (-1) ÷ 2 - 4  = -2 ÷ -2 = 1

-1 and 1 are opposite and reciprocal so m∡Q = 90°

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3 years ago
Eight friends ate at a restaurant and agreed to share the bill equally. Because Judi forgot her money, each of her seven friends
galina1969 [7]
Judi's share was  (7 x $2.50) =  $17.50 .

That was really one share out of eight.
So the total bill was

                             (8 x $17.50) =   $140.00 .
5 0
3 years ago
Given that sec0=-37/12 what is the value of cot0, for Pi/2&lt;0
inysia [295]

Answer:

Step-by-step explanation:

12/35

3 0
2 years ago
A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. ​(a) Describe the
Ivanshal [37]

Answer:

a) \bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

b) z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

c) z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

d) z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

\mu = 83, \sigma = 27

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

Part b

We want this probability:

P(\bar X>89)

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 89 we got:

z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

Part c

P(\bar X

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 75.65 we got:

z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

Part d

We want this probability:

P(79.4 < \bar X < 89.3)

We find the z scores:

z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

8 0
3 years ago
Perform the operation and write the answer in simplest form 5 1/7 * 3 1/9
solong [7]

Answer:

16

Step-by-step explanation:

Input it in the calculator

8 0
3 years ago
Read 2 more answers
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