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3 years ago

If it takes 42 minutes to load 3 1/2 trucks, how many minutes will it take to load 6 1/2 trucks?

1 answer:

6 0

If it takes 42 minutes to load 3 1/2 trucks, then it takes 42 / 3.5 = 12 minutes to load a single truck. Multiplying the number of minutes per truck by 6.5 yields the time it will take to load. In this case 12 x 6.5 = 78 minutes would be required to load 6 1/2 trucks. The formula for the time taken is t = 12n, where t is the time in minutes and n is the number of trucks.

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how far can a mother push a 20.0kg baby carriage, using a force of 62.0N at angle of 30.0°to the horizontal, if she can do 2920

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Here is my solution using my app.

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4 years ago

Let's say you are on the third story of an apartment building that has a swimming pool. For some insane reason you think it is a

labwork [276]

Answer:

To make it into the pool you must run and jump at

$\displaystyle v_o=x.\sqrt{\frac{g}{2y}}$

Explanation:

Horizontal Launch

When an object is thrown with a specified initial speed in the horizontal direction, it describes a curved path that finishes when it hits the ground level after traveling certain horizontal distance x and a vertical height y from the launching point. The horizontal speed is always constant and the vertical speed increases due to the effect of gravity. It can be found that the horizontal distance reached by the object when launched at an initial speed in a given time t is

$x=v_o.t$

And the vertical distance is

$\displaystyle y=\frac{g.t^2}{2}$

If t is the total flight time, then x and y are maximum and we can find a relation between them. Solving for t in the first equation

$\displaystyle t=\frac{x}{v_o}$

Substituting in the second equation

$\displaystyle y=\frac{g}{2}\left ( \frac{x}{v_o}\right )^2$

Rearranging

$\displaystyle \left ( \frac{v_o}{x}\right )^2=\frac{g}{2y}$

Solving for $v_o$

$\displaystyle v_o=x.\sqrt{\frac{g}{2y}}$

There are many applications for the horizontal launch. One common situation is when someone wants to drop something on certain terrain at a specific approximate point when traveling in a plane at a given height. Once the object is left fall, it has the same speed as the plane, so the plane speed can be estimated to make the best possible launch, or given that speed, we can know in advance where the object will reach ground level

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3 years ago

Large waves produced by earthquakes

galina1969 [7]

Answer:

Explanation:

If the earthquake occus in the ocean, it can push up powergul waves.

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3 years ago

Read 2 more answers

Physics question plz help

blagie [28]

Answer:

B. $30\,s\,< t \le 40\,s$ .

Explanation:

The vehicle is travelling eastwards when its velocity is positive and westwards when velocity is negative. According to the graph, $v > 0$ for $30\,s\,< t \le 40\,s$ . Hence, correct answer is B.

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3 years ago

A spring whose stiffness is 3500 N/m is used to launch a 4 kg block straight up in the classroom. The spring is initially compre

jarptica [38.1K]

Answer:

the speed of the block at the given position is 21.33 m/s.

Explanation:

Given;

spring constant, k = 3500 N/m

mass of the block, m = 4 kg

extension of the spring, x = 0.2 m

initial velocity of the block, u = 0

displacement of the block, d =1.3 m

The force applied to the block by the spring is calculated as;

F = ma = kx

where;

a is the acceleration of the block

$a = \frac{kx}{m} \\\\a = \frac{(3500) \times (0.2)}{4} \\\\a = 175 \ m/s^2$

The final velocity of the block at 1.3 m is calculated as;

v² = u² + 2ad

v² = 0 + 2ad

v² = 2ad

v = √2ad

v = √(2 x 175 x 1.3)

v = 21.33 m/s

Therefore, the speed of the block at the given position is 21.33 m/s.

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3 years ago