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alisha [4.7K]
3 years ago
10

If a wave has amplitude of 2 meters, a wavelength of 2 meters, and a frequency of 10 Hz, and a period of 1 second, then at what

speed is the wave moving?
Physics
1 answer:
Serhud [2]3 years ago
6 0

Answer:

20 m/s

Explanation:

The speed of a wave is given by:

v=\lambda f

where

\lambda is the wavelength

f is the frequency

v is the speed

For the wave in this problem,

f = 10 Hz is the frequency

\lambda=2 m is the wavelength

So the speed is

v=(10 Hz)(2 m)=20 m/s

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Given a volume of 1000. cm^3 of an ideal gas at 300. K, what volume would it occupy at a temperature of 600. K?
Inessa [10]

Answer:2000cm3

Explanation: this is Charles' law which has the expression V1/T1 = V2/T2

Making V2 the subject of the formula, we have that

V2 = V1 x T2/ T1

= 1000 x 600 / 300

= 2000cm3

Where:

V1= initial velocity

V2= Final velocity

T1= initial temperature

T2= Final temperature

6 0
3 years ago
An open vertical tube has water in it. a tuning fork vibrates over its mouth. as the water level is lowered in the tube, a reson
bagirrra123 [75]
Since any first distanced1=λ(2N1−1)/4, whereN1= 1,2,3,· · ·will do, the first distance only cannot be used to know the wavelength.The space between the resonances is ½ a wavelength, soλ= 2 [d2−d1]= 2 [(35 cm)−(25 cm)]= 20 cm.
The frequency isF = vλ=343 m/s2 [(35 cm)−(25 cm)]= 1715 Hz.
6 0
4 years ago
A spring has a length of .200 m when a .300 kg hangs from it,and a length of .750 m when a 1.95 kg hangs from it.what is the for
musickatia [10]

1) 29.5 N/m

2) 0.100 m

Explanation:

1)

The force constant of the spring can be found by using the fact that the force on the spring is proportional to the extension of the spring (Hooke's Law). Therefore, we can write:

\Delta F= k \Delta x

where

\Delta F = F_2 - F_1 is the change in the force on the spring, where

F_1 = m_1 g = (0.300)(9.8)=2.94 N is the force applied when the hanging mass is

m_1 = 0.300 kg

F_2 = m_2 g = (1.95)(9.8)=19.1 N is the force applied when the hanging mass is

m_2 = 1.95 kg

\Delta x=x_2 -x_1 is the change in extension of the spring, where

x_1=0.200 m is the extension of the spring when the hanging mass is 0.300 kg

x_2=0.750 m is the extension of the spring when the hanging mass is 1.95 kg

Solving for k,

k=\frac{F_2-F_1}{x_2-x_1}=\frac{19.1-2.94}{0.750-0.200}=29.5 N/m

2)

When the first mass is hanging on the spring, we have

F_1 = k (x_1 - x_0)

where:

F_1 is the force applied on the spring (the weight of the hanging mass)

k is the spring constant

x_1 is the extension of the spring wrt its natural length

x_0 is the natural length of the spring (the unloaded length)

Here we have

F_1=2.94 N

k = 29.5 N/m

x_1=0.200 m

Solving for x_0, we find:

x_0 = x_1 - \frac{F_1}{k}=0.200 - \frac{2.94}{29.5}=0.100 m

5 0
3 years ago
Which resistors in the circuit are connected in series?
Lisa [10]

Answer:

it's C and D... do you understand?

7 0
3 years ago
A minivan sells for 33,200 dollars. Give the price of the minivan in a) kilodollars and megadollars
amm1812
The prefix of a unit could give you a hint on its extent with respect to the base unit. In this case, the base unit is money in terms of dollars. When you say kilodollars, that would be 1,000 times as large as a dollar. Hence,

33,200 dollars * 1 kilodollar/ 1,000 dollars =  33.2 kilodollars

When you say megadollars, that would be a million times as large as a dollar. Hence,

33,200 dollars * 1 megadollar/1,000,000 dollars = 0.0332 megadollars

6 0
4 years ago
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