Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.
-2x+3y=-6 Add 2x in both sides
3y=2x-6 Divide by 3 in both sides to isolate y
y=2/3x-6/3
The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.
y=mx+b Substitute the given point and the previous slope found
-2=(-3/2)(6)+b Combine like terms
-2=-9+b Add 9 in both sides to isolate b
7=b
The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.
Answer:
C. both student 1 and student 2
Step-by-step explanation:
Dilation does not change any angles, so the triangles are similar and the trig functions of corresponding angles will be identical.
The slope of CB is -1/3 and the slope of BA is 3, so they multiply together to give -1. That means the segments are at right angles and the triangle is a right triangle.
Both the premise and the conclusion of each student is correct.
Answer:
Divide the numerator and denominator of the given rate by the denominator of the given rate.
Step-by-step explanation:
This is FLVS Virtule school what are your grade and teachers
Descending Order:
a. 15, 8, 0, -2, -3, -5
b. 23, 12, 7, 6, 0, -11
c. 12, 11, 5, -1, -21, -31
d. 98, 56, 4, 0, -35, -53
Ascending (increasing) Order:
a. -333, -210, -26, -8, 0, 21, 33, 85, 2011
b. -8, -5, -1, 0, 4, 5
c. -7, -6, -3, 0, 2, 3, 4
d. -7, -3, -1, 0, 3, 8, 17
e. -10, -7, -6, 5, 6, 19
