Answer:
41.74 m/s
Explanation:
The energy used to draw the bowstring = the kinetic energy of the arrow.
Fd = 1/2mv²................................ Equation 1
Where F = force, d = distance move string, m = mass of the arrow, v = speed of the arrow.
make v the subject of the equation
v = √(2Fd/m)...................... Equation 2
Given: F = 201 N, m = 0.3 kg, d = 1.3 m.
Substitute into equation 2
v = √(2×201×1.3/0.3)
v = √(1742)
v = 41.74 m/s.
Hence the arrow leave the bow with a speed of 41.74 m/s
Your answer would be A. You divide 96 by 16 to find the answer
Answer:
Part a)
part b)
Part c)
Part d)
here since wave is moving in negative direction so the sign of 
must be positive
Explanation:
As we know that the speed of wave in string is given by
so we have
now we have
now we have
Part a)
= amplitude of wave
part b)
here we know that
so we have
Part c)
Part d)
here since wave is moving in negative direction so the sign of must be positive
3 bulbs are in series and if the same 3 bulbs are in parallel with the same battery then the bulbs that are connected in parallel will be dimmer
<h3>What is power?</h3>
The rate of doing work is known as power. The Si unit of power is the watt.
Power =work/time
The mathematical expression for the electric power is as follows
P = VI
The same current flows through both bulbs when they are connected in series. A greater voltage drop across the bulb with the higher resistance will result in higher power dissipation and brightness. In the case of the parallel combination, the bulb will be dimmer
Thus, If the same three bulbs are connected in series and parallel with the same battery, the parallelly connected bulbs will be dimmer, therefore the correct option is A
Learn more about power from here
brainly.com/question/3854047
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Answer:
5.78amps
Explanation:
Given data
Time t= 57 seconds
Charge Q= 330C
Current I= ??
The expression for the electric current is given as
Q= It
Substituting we have
330= I*57
I= 330/57
I=5.78 amps
Hence the current is 5.78amps
