Answer:
1000 cm.
Explanation:
To obtain the estimated tree height :
(Height of rod / length of rod shadow) = (height of tree / length of tree shadow)
Substituting values into the formula :
(150cm / 120 cm) = (height of tree / 800 cm)
Using cross multiplication :
Height of tree * 120 = 150 * 800
Height of tree = (150 * 800) / 120
Height of tree = 120,000 / 120
Height of tree = 1000
Hence, estimate height of tree = 1000 cm
Answer:
a) 12.8 N
b) 3.2 m/s²
Explanation:
I'm guessing the period is 0.5π s.
Period of a spring in simple harmonic motion is:
T = 2π √(m/k)
Given T = 0.5π and m = 2 kg:
0.5π = 2π √(2/k)
0.25 = √(2/k)
0.0625 = 2/k
k = 32
The spring constant is 32 N/m, and the maximum displacement is 0.4 m. The maximum force can be found with Hooke's law:
F = kx
F = (32 N/m) (0.4 m)
F = 12.8 N
The acceleration can be found with Newton's second law:
∑F = ma
kx = ma
(32 N/m) (0.2 m) = (2 kg) a
a = 3.2 m/s²
Answer:
1.02 seconds
Explanation:
Initial velocity = u = 5 m/s
t = Time taken
s = Displacement travelled = 0
a = Acceleration due to gravity = -9.81 m/s² (negative sign due to direction)
Equation of motion
So, time taken to return to its initial position is 1.02 seconds
Answer:
Explanation:
a) using the energy conservation equation
mgh = 0.5mv^2 + 0.5Iω^2
I(moment of inertia) (basket ball) = (2/3)mr^2
mgh = 0.5mv^2 + 0.5( 2/3mr^2) ( v^2/r^2)
gh = 1/2v^2 + 1/3v^2
gh = v^2( 5/6)
v = 
putting the values we get
solving for h( height)
h = 3.704 m apprx
b) velocity of solid cylinder
mgh = 0.5mv^2 + 0.5( mr^2/2)( v^2/r^2) where ( I ofcylinder = mr^2/2)
g*h = 1/2v^2 + 1/4v^2
g*h = 3/4v^2
putting the value of h and g we get
v= = 6.957 m/s apprx
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