Answer:
W = 0.49 N
τ = 0.4851 Nm
Force
Explanation:
The weight force can be found as:
W = mg
W = (0.05 kg)(9.8 m/s²)
<u>W = 0.49 N</u>
The torque about the pivot can be found as:
τ = W*d
where,
τ = torque
d = distance between weight and pivot = 99 cm = 0.99 m
Therefore,
τ = (0.49 N)(0.99 m)
<u>τ = 0.4851 Nm</u>
The pivot exerts a <u>FORCE </u>on the meter stick because the pivot applies force normally over the stick and has a zero distance from stick.
The pertinent equation here is F=ma. You haven't shared the mass of the box, so I will use M to represent that mass.
Then F = M(<span>2.3 m/s^2) (answer)</span>
I’m pretty sure you times them so 1 with A, 2 with e, 3 with C, and 4 with B
Answer:m1v1 + m2v2 = (m1f + m2f)vf. 3000kg(10.0m/s) + (15000kg)(0.0m/s) = (18000kg)(vf).
Explanation:
Answer:
33.6 m
Explanation:
Given:
v₀ = 0 m/s
a = 47.41 m/s²
t = 1.19 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (0 m/s) (1.19 s) + ½ (47.41 m/s²) (1.19 s)²
Δx = 33.6 m
