Ask question

Ask question

All categories

3 years ago

5

A sound wave has a frequency of 615 hz in air and a wavelength of 0.54 m. what is the temperature of the air? assume the velocit

y of sound at 0◦c is 335 m/s. answer in units of ◦c.

1 answer:

Leno4ka [110]3 years ago

6 0

Answer is: T = -4.706°C

Explanation: Please see the image attached with this answer.

You might be interested in

Five scientist who travelled to space

Masja [62]

Answer:

The Most Famous Astronomers of All Time. Karl Tate, SPACE.com. ...

Claudius Ptolemy. Bartolomeu Velho, Public Domain. ...

Nicolaus Copernicus. Public Domain. ...

Johannes Kepler. NASA Goddard Space Flight Center Sun-Earth Day. ...

Galileo Galilei. NASA

6 0

3 years ago

A crime suspect fled the scene when police officers entered the building. How far could he run in 10 minutes if he can run 5 mil

emmainna [20.7K]

(5 mi/hr) x (1hr/60min) x (10min) = 5 x 10 / 60 = <em>5/6 mile</em>

(5/6 mile) x (1,760 yd/mile) = <em>1,466 and 2/3 yards</em>

3 0

3 years ago

Compare and contrast the health benefits and the amount of physical or mental energy needed between active leisure activities an

dolphi86 [110]

This is the answer "Some active leisure activities, such as yoga and running, require a great deal of physical energy, while other activities, like playing chess, require a substantial amount of mental energy. Passive leisure activities, such as watching TV or going to the movies, require little to no physical or mental energy. Because of the exertion of physical or mental energy, active leisure activities have more health benefits than passive leisure activities." hope it help you?:)

4 0

3 years ago

In an engine governor, the two spheres (total mass of 1.0kg) are at 0.05m and rotating at 37rad/s If the engine increases the an

kirill115 [55]

Here we can say that there is no external torque on this system

So here we can say that angular momentum is conserved

so here we will have

$I_1\omega_1 = I_2\omega_2$

now we have

$I_1 = mr^2$

$I_1 = (1kg)(0.05^2)$

$I_1 = 25\times 10^{-4} kg m^2$

similarly let the final distance is "r"

so now we have

$I_2 = mr^2$

$I_2 = 1r^2$

now from above equation we have

$(25\times 10^{-4})37 = (r^2)(58)$

$r = 0.04 m$

so final distance is 0.04 m between them

8 0

3 years ago

The pressure of a gas is 15 atm in a 5L cylinder. If the volume of the cylinder is depressed to 3L, What is the new pressure exe

disa [49]

P1v1=p2v2. 15x5=p2x3

5 0

3 years ago