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anastassius [24]
3 years ago
11

A zebra starts from rest and accelerates at 1.9 m/s how far has a zebra gone in five seconds

Physics
1 answer:
Maksim231197 [3]3 years ago
5 0
To that multiply 1.9 by 5 to get 9.5.  The zebra has gone 9.5 m.
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Two force vectors are oriented such that the angle between their directions is 38 degrees and they have the same magnitude. If t
Usimov [2.4K]

Answer:

Sum of the forces will be equal to 3.479 N

Explanation:

We have given two same forces are oriented at an angle of 38°

Magnitude of each force is given F_1=F_2=1.84

We have to find the sum of the forces

Sum of the forces will be equal to

F=\sqrt{F_1^2+F_2^2+2F_1F_2cos\Theta }

So sum of the forces will be equal to F=\sqrt{1.84^2+1.84^2+2\times 1.84\times 1.84\times cos38^{\circ} }=3.479

So sum of the force will be equal to 3.479 N

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3 years ago
What is the difference between first aid and first aid kit
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2 years ago
!!! 100 POINTS !!! PLEASE HELP !!!
hram777 [196]

Q1. Option 2: basketball


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8 0
3 years ago
Read 2 more answers
If an object's velocity changes from 25 meters per second to
damaskus [11]

Answer:

B

Explanation:

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3 0
3 years ago
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An initially uncharged 3.47-μF capacitor and a 6.43-kΩ resistor are connected in series to a 1.50-V battery that has negligible
harkovskaia [24]

Answer: a) io=233.28 A ( initial current); b) τ=R*C= 22.31 ms; c) 81.7 ms

Explanation:  In order to explain this problem we have to use, the formule for the variation of the current in a RC circuit:

I(t)=io*Exp(-t/τ)

and also we consider that io=V/R=(1.5/6.43*10^3)

=233.28 A

then the time constant for the RC circuit is τ=R*C=6.43*10^3*3.47*10^-6

=22.31 ms

Finally the time to reduce the current to 2.57% of its initial value is obtained from:

I(t)=io*Exp(-t/τ)  for I(t)/io=0.0257=Exp(-t/τ) then

ln(0.0257)*τ =-t

t=-ln(0.0257)*τ=81.68 ms

3 0
3 years ago
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