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vfiekz [6]
3 years ago
7

An ornament of mass 42.0 g is attached to a vertical ideal spring with a force constant (spring constant) of 33.9 N/m. The ornam

ent is then lowered very slowly until the spring stops stretching. How much does the spring stretch?
Physics
1 answer:
Maslowich3 years ago
4 0

Answer:

Extension is 12.14m

Explanation:

mass of ornament=42g,weight of ornament=mg=42*9.8=411.6

Force constant(k)= 33.9N/m

F=ke

e=F/k

F is force, e is extension

F=weight of ornament

e=411.6/33.9

e=12.14m

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Answer: 56.87m/s^{2}

Explanation:

If we make an analysis of the net force F_{net} of the rock that was thrown upwards, we will have the following:

F_{net}=F_{up}-W  (1)

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Being the weight the relation between the mass m=3kg of the rock and the acceleration due gravity g=9.79m/s^{2} :

W=m.g=(3kg)(9.79m/s^{2}) (2)

W=29.37 N (3)

Substituting (3) in (1):

F_{net}=200N-29.37 N  (4)

F_{net}=170.63 N  (5) This is the net Force on the rock

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F_{net}=m.a  (6)

Finding the acceleration a:

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a=\frac{170.63 N}{3kg} (8)

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