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vfiekz [6]
3 years ago
7

An ornament of mass 42.0 g is attached to a vertical ideal spring with a force constant (spring constant) of 33.9 N/m. The ornam

ent is then lowered very slowly until the spring stops stretching. How much does the spring stretch?
Physics
1 answer:
Maslowich3 years ago
4 0

Answer:

Extension is 12.14m

Explanation:

mass of ornament=42g,weight of ornament=mg=42*9.8=411.6

Force constant(k)= 33.9N/m

F=ke

e=F/k

F is force, e is extension

F=weight of ornament

e=411.6/33.9

e=12.14m

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Answer:

35870474.30504 m

Explanation:

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From Kepler's law we have relation

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Explanation:

First of all, we need to calculate the acceleration of the hockey player, which is given by:

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