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amm1812
3 years ago
13

Radio waves travel at the speed of light. What is the wavelength of a radio signal with a frequency of 9.45 x 10^7 Hz?

Physics
1 answer:
Klio2033 [76]3 years ago
3 0

Answer:

So I never really knew you

God, I really tried to

Blindsided, addicted

Felt we could really do this

But really I was foolish

Hindsight, it's obvious

Explanation:

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When an average force F is exerted over a certain distance on a shopping cart of mass m, its kinetic energy increases by 12mv2.
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Explanation:

Given that

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b)

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8 0
3 years ago
Two titanium spheres approach each other head-on with the same speed and collide elastically. After the collision, one of the sp
Thepotemich [5.8K]
I know i did part a correctly. heres what i did: momentum is conserved: m1 * u - m2 * u = m2 * v or (m1 - m2) * u = m2 * v Also, for an elastic head-on collision, we know that the relative velocity of approach = relative velocity of separation (from conservation of energy), or, for this problem, 2u = v Then (m1 - m2) * u = m2 * 2u m1 - m2 = 2 * m2 m1 = 3 * m2 m1 is the sphere that remained at rest (hence its absence from the RHS), so m2 = 0.3kg / 3 m2 = 0.1 kg b) this part confuses me, heres what i did (m1 - m2) * u = m2 * v (.3kg - .1kg)(2.0m/s) = .1kg * v .4 kg = .1 v v = 4 m/s What my teacher did: (.3g - .1g) * 2.0m/s = (.3g + .1g) * v I understand the left hand side but i dont get the right hand side. Why is m1 added to m2 when m1 is at rest which makes its v = zero?? v = +1.00m/s since the answer is positive, what does that mean? Also, if v was -1.00m/s what would that mean? thanks!

<span>Reference https://www.physicsforums.com/threads/elastic-collision-with-conservation-of-momentum-problem.651261...</span>
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