Answer:
- ength (l) : (10-2*5/3) = 20/3
- width(w): (10 - 2*5/3) = 20/3
- height(h): 5/3
Step-by-step explanation:
Let x is the side of identical squares
By cutting out identical squares from each corner and bending up the resulting flaps, the dimension are:
- length (l) : (10-2x)
- width(w): (10-2x)
- height(h): x
The volume will be:
V = (10-2x) (10-2x) x
<=> V = (10x-2
) (10-2x)
<=> V = 100x -20 - 20 + 4
<=> V = 4 - 40 + 100x
To determine the dimensions of the largest box that can be made, we need to use the derivative and and set it to zero for the maximum volume
dV/dx = 12 -80x + 100
<=> 12 -80x + 100 =0
<=> x = 5 or x= 5/3
You know 'x' cannot be 5 , because if we cut 5 inch squares out of the original square, the length and the width will be 0. So we take x = 5/3
=>
- length (l) : (10-2*5/3) = 20/3
- width(w): (10 - 2*5/3) = 20/3
- height(h): 5/3
Answer:
y = 2x−2
Step-by-step explanation:
You are given a slope and a point, so you can write the equation using point-slope form:
y -k = m(x -h) . . . . . . a line with slope m through point (h, k)
Putting in the numbers given, you have ...
y -6 = 2(x -4)
y = 2x -8 +6 . . . . eliminate parentheses, add 6
y = 2x -2 . . . . . . . collect terms.
__
You know that the slope is the coefficient of x, so the first choice is eliminated right away. Trying the point values in the other equations shows you that they only work for the last choice, as shown above.
- 2·4 +14 = 22 ≠ 6 . . . . second choice doesn't work
- 2·4 +6 = 14 ≠ 6 . . . . . third choice doesn't work
- 2·4 -2 = 6 . . . . . . y = 2x-2 is the equation that works
Answer:
128 ft / second.
Step-by-step explanation:
It's acceleration is due to gravity and is 32 ft s^-2.
To find the velocity when it hits the ground we use the equation of motion
v^2 = u^2 + 2gs where u = initial velocity, g = acceleration , s = distance.
v^2 = 0^2 + 2 * 32 * 256
v^2 = 16384
v = 128 ft s^-1.
The answer will be 46,200 Hopes this helps. :)
I need to know the rest of the question in order to help you! :D
