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3 years ago

Probability question. Please answer with work attached.

Mathematics

1 answer:

Helga [31]3 years ago

3 0

Step-by-step Answer:

There is a total of 10 coins, 5 dimes, 2 quarters and three pennies.

By picking a coin, it could be any that shows up out of the 10, so the probability of picking any coin in particular is 1 / 10.

If there are 5 dimes, the probability of picking ANY one particular dime is 1/10, so with 5, the probability of picking ANY of the five dimes is 5/10 = 1/2.

Going along the same line of thought, the probability of picking any of quarters and pennies would be 2/10+3/10 = 5/10 = 1/2 as well.

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tatyana61 [14]

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3 years ago

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Sati [7]

Answer:

$b=\frac{4c-a^{2} }{3}$

Step-by-step explanation:

First: multiply both sides by 4. 4 times c is 4c and the other sides cancels out as you are doing the inverse operation of division

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Subtract both sides by a squared

DO NOT TAKE THE SQUARE ROOT! This is because it is a squared plus 3b so you have to do the inverse of addition

From that you get $4c-a^{2} =3b$

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klemol [59]

Answer:

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