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Alenkasestr [34]
4 years ago
6

Calculate the energy required to move from solid water at 0 degrees C to liquid water at 0 degrees C

Chemistry
1 answer:
Serhud [2]4 years ago
7 0

Answer:

Q = 334\,kJ

Explanation:

Let assume that 1 kilogram of water in solid state at one atmosphere of pressure. The fussion latent heat of 334\,\frac{kJ}{kg}, the heat required to change the phase of water is:

Q = m \cdot L_{f}

Q = (1\,kg)\cdot \left(334\,\frac{kJ}{kg} \right)

Q = 334\,kJ

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hich of the followings decrease the affinity of adult Hb with O2? A. 2,3 BPG B. hydrogen ion C. CO2 D. Ferrous ion
Ivahew [28]

Answer:

A. 2,3 BPG

Explanation:

2,3-bisphosphoglycerate (BPG), otherwise known as 2,3-DPG, enables the transition of hemoglobin from a very high-oxygen-affinity state to a reduced-oxygen-affinity state.

Tissues hemoglobin oxygen affinity is reduced by numerous physiological factors including.

1. Temperature Increased,

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4. 2,3-Bisphosphoglycerate (2,3-BPG)

all of which can contribute to decrease the oxygen affinity of hemoglobin which favours unloading and increased oxygen availability to our body cells.

3 0
3 years ago
When 50 ml of 1.5 M HCl is added to 100 ml of 1.5 M sodium hydroxide solution, temperature
Georgia [21]

Answer:

Q = -1.318 KJ

Explanation:

We will use the assumption that this solution acts like water and thus we will use the specific heat capacity of water and when converting from mL to g, we will use the conversion like we do for water.

We are told that 50 mL of HCl reacts with 100 mL of NaOH.

Thus total mass; m = 50 + 100 = 150 mL

Converting to grams gives 150 g since we have assumed that the solution behaves like water.

We are given;

Initial temperature; T_i = 21.3° C

Final temperature; T_f = 23.4° C

ΔT = 23.4 - 21.3

ΔT = 2.1°C

Formula for quantity of heat is;

Q = mcΔT

c is specific heat capacity.

We will use c = 4.184 J/g°C since the solution is assumed to behave like water.

Thus;

Q = -(150 × 2.1 × 4.184)

Q = -1317.96 J

Negative sign is used because temperature was raised and thus reaction is exothermic.

Approximation to KJ gives; -1.318 KJ

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through water

Explanation:

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