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MrMuchimi
3 years ago
8

Https://ny.pbslearningmedia.org/resource/chemical-engineering-your-future/chemical-engineering-video/

Chemistry
1 answer:
nlexa [21]3 years ago
8 0

Both disciplines deal with much the same things and there is much overlap, but the basic differences are novelty and scale. It is sometimes said that a chemist wears a lab coat; a chemical engineer wears a hard hat.

Explanation:

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Yes they are what are your options
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if five gases contained in a cylinder each exert a pressure of 1.0 atm what is the total pressure exerted by the gases
UNO [17]

Answer:5.0 atm

Explanation:

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6 0
3 years ago
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If you have 40 grams of potassium nitrate in 100 grams of water at 20 C:
anygoal [31]

Answer:

Explanation:The final homogenous solution, after cooling it to 40°C, will contain 47 g of potassium sulfate disolved in 150 g of water, so you can calculate the amount disolved per 100 g of water in this way:

[47 g of solute / 150 g of water] * 100 g of g of water = 31.33 grams of solute in 100 g of water.

So, when you compare with the solutiblity, 15 g of solute / 100 g of water, you realize that the solution has more solute dissolved with means that it is supersaturated.

To make a saturated solution, 15 grams of potassium sulfate would dissolve in 100 g of water.

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7 0
3 years ago
The air bags in cars are inflated when a collision triggers the explosive, highly exothermic decomposition of sodium azide (NaN3
Oksanka [162]

Answer : The mass of NaN_3 required is, 166.4 grams.

Explanation :

First we have to calculate the moles of nitrogen gas.

Using ideal gas equation:

PV=nRT

where,

P = Pressure of N_2 gas = 1.00 atm

V = Volume of N_2 gas = 113 L

n = number of moles N_2 = ?

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of N_2 gas = 85^oC=273+85=358K

Putting values in above equation, we get:

1.00atm\times 113L=n\times (0.0821L.atm/mol.K)\times 358K

n=3.84mol

Now we have to calculate the moles of sodium azide.

The balanced chemical reaction is,

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

From the balanced reaction we conclude that

As, 3 mole of N_2 produced from 2 mole of NaN_3

So, 3.84 moles of N_2 produced from \frac{2}{3}\times 3.84=2.56 moles of NaN_3

Now we have to calculate the mass of NaN_3

\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3

Molar mass of NaN_3 = 65 g/mole

\text{ Mass of }NaN_3=(2.56moles)\times (65g/mole)=166.4g

Therefore, the mass of NaN_3 required is, 166.4 grams.

3 0
3 years ago
How do you solve (1 x 1025) =3 x 10
Mrrafil [7]

Hey There!!~

Your best answer choice is 10280 or 10,280.

Because, 1 x 1025 = 1025 + 3 = 1028 x 10 = 10280 or 10,280.

Hope This Helps....!!

4 0
3 years ago
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