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MrMuchimi
3 years ago
8

Https://ny.pbslearningmedia.org/resource/chemical-engineering-your-future/chemical-engineering-video/

Chemistry
1 answer:
nlexa [21]3 years ago
8 0

Both disciplines deal with much the same things and there is much overlap, but the basic differences are novelty and scale. It is sometimes said that a chemist wears a lab coat; a chemical engineer wears a hard hat.

Explanation:

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Knowing that the distances the truck traveled during each segment were 30, 45, 50, and 65 respectively, what was the total dista
Sholpan [36]

Answer:

The distance the truck traveled is 190

Explanation:

I added 30, 45, 50, 65 together to get the total distance

5 0
3 years ago
g How many moles of NaOH are present in a sample if it is titrated to its equivalence point with 44.02 mL of 0.0885 M H2SO4? 2Na
Lisa [10]

Answer:

n_{base}=3.90x10^{-3}molNaOH

Explanation:

Hello!

In this case, since the sulfuric acid and sodium hydroxide react in a 1:2 mole ratio, given the reaction, we realize they have the following mole ratio at the equivalence point:

2*n_{acid}=n_{base}

Which in terms of concentrations and volumes is:

2*M_{acid}V_{acid}=n_{base}

Thus, we can plug in the volume and concentration of acid to find the moles of base:

n_{base}=0.04402L*0.0885\frac{mol}{L} \\\\n_{base}=3.90x10^{-3}molNaOH

Best regards!

8 0
3 years ago
Iodine is a solid nonmetal. What is one property of iodine?
KiRa [710]

Answer:

The correct answer is B. Dull appearance

Explanation:

6 0
3 years ago
The procedure for testing your unknown solution in this week's lab is identical to the procedure which you conducted in Week 1.
lawyer [7]

Answer:

The correct answer is option C. The unknown solution definitely has Hg22+ present.

Explanation:

In the analysis of group 1 metal cation, the unknown solution is treated with sufficient quantity of 6 M HCl solution and if group 1 metal cations are present then white precipitate of Agcl, PbCl2 or Hg2Cl2 is formed. The precipitate of PbCl2 is soluble in hot water but the other two remains insoluble after treating with hot water. Precipitate of AgCl disappears upon treatment of NH3 solution but Hg2Cl2 becomes black in the reaction with NH3. The black Colour appears due to the formation of metallic Hg.

Balanced chemical equation of the reation is -

Hg2Cl2 + 2NH3  ---------> HgNH2Cl (white ppt.) + Hg (black ppt.) + NH4Cl

Therefore, from the given information the conclusion which can be drawn is that the unknown solution definitely has Hg22+ present.

8 0
3 years ago
Read 2 more answers
6 Li + Zn3(PO4)2 ------- > 2 Li3PO4 + 3 Zn
bogdanovich [222]

Moles of Lithium phosphate : 0.495

<h3>Further explanation</h3>

Given

6 Li + Zn₃(PO₄)₂ ------- > 2 Li₃PO₄ + 3 Zn

Required

Moles of Lithium phosphate

Solution

moles of Zinc(Ar=65,38 g/mol) :

= mass : Ar

= 48.6 : 65.38

= 0.743

From equation, mol ratio of Zn :  Li₃PO₄ = 3 : 2, so mol  Li₃PO₄ :

= 2/3 x mol Zn

= 2/3 x 0.743

= 0.495

3 0
3 years ago
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