We know that the interest decreased by 29.3%, therefore
what was left now is simply just 70.7% of the original, therefore we divide
this by 0.707
rate = 7.7% / 0.707
rate = 10.89%
<span>So the rate was 10.89% 10 years ago</span>
Answer:
Solution given:
Sin

equating corresponding value
opposite=-24
hypoyenuse=25
adjacent=x
By using Pythagoras law
hypotenuse²=opposite²+adjacent²
25²=(-24)²+x²
625=576+x²
x²=625-576
x=49
x=
In IV quadrant
Cos angle is positive
Cos
<h3>Cos

</h3>
Answer:
x = 26
Step-by-step explanation:
x + 104 = 5x
104 = 4x
x = 26
Set up a system of equations and say green route is x and blue route is y
This will give you
Monday 6x + 5y= 52
Tuesday 12x + 13y = 119
Solve by multiplying the top equation by two to get
12x + 10y= 104
Since you have 12x in both equations, these cancel out when you subtract the bottom from the top. This leaves you with
-3y=-15
Y=5
The blue route is 5 miles, but they want to know the green route. Fill in the y value in either one of your equations. Let’s use the one from Tuesday
12x + 13 (5) = 119
12x= 54
X= 4.5
This means that the answer is B, 4.5 miles
Answer:
Step-by-step explanation:
When a question asks for the "end behavior" of a function, they just want to know what happens if you trace the direction the function heads in for super low and super high values of x. In other words, they want to know what the graph is looking like as x heads for both positive and negative infinity. This might be sort of hard to visualize, so if you have a graphing utility, use it to double check yourself, but even without a graph, we can answer this question. For any function involving x^3, we know that the "parent graph" looks like the attached image. This is the "basic" look of any x^3 function; however, certain things can change the end behavior. You'll notice that in the attached graph, as x gets really really small, the function goes to negative infinity. As x gets very very big, the function goes to positive infinity.
Now, taking a look at your function, 2x^3 - x, things might change a little. Some things that change the end behavior of a graph include a negative coefficient for x^3, such as -x^3 or -5x^3. This would flip the graph over the y-axis, which would make the end behavior "swap", basically. Your function doesn't have a negative coefficient in front of x^3, so we're okay on that front, and it turns out your function has the same end behavior as the parent function, since no kind of reflection is occurring. I attached the graph of your function as well so you can see it, but what this means is that as x approaches infinity, or as x gets very big, your function also goes to infinity, and as x approaches negative infinity, or as x gets very small, your function goes to negative infinity.