1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vovikov84 [41]
3 years ago
8

The rectangular coils in a 345-turn generator are 12 cm by 12 cm. Part A

Physics
1 answer:
Likurg_2 [28]3 years ago
4 0

Answer:

118.166 volt

Explanation:

We have given number of turns N =345

Sides of the rectangular coils is 12 cm =0.12 m

So area A =0.12×0.12=0.0144 m^2

Magnetic field B =0.45 T

Angular speed =505 rpm

Speed in rad/sec \omega =\frac{2\pi N}{60}=\frac{2\times 3.14\times 505}{60}=52.8566rad/sec

The emf is given by E=NAB\omega SIN\omega t

For maximum emf sinwt =1

So E=345\times 0.0144\times 0.45\times 52.8566=118.166volt

You might be interested in
By what potential difference must a proton [m_0 = 1.67E-27 kg) be accelerated to have a wavelength lambda = 4.23E-12 m? By what
Vinil7 [7]

Explanation:

1. Mass of the proton, m_p=1.67\times 10^{-27}\ kg

Wavelength, \lambda_p=4.23\times 10^{-12}\ m

We need to find the potential difference. The relationship between potential difference and wavelength is given by :

\lambda=\dfrac{h}{\sqrt{2m_pq_pV}}

V=\dfrac{h^2}{2q_pm_p\lambda^2}

V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 1.67\times 10^{-27}\times (4.23\times 10^{-12})^2}

V = 45.83 volts

2. Mass of the electron, m_p=9.1\times 10^{-31}\ kg

Wavelength, \lambda_p=4.23\times 10^{-12}\ m

We need to find the potential difference. The relationship between potential difference and wavelength is given by :

\lambda=\dfrac{h}{\sqrt{2m_eq_eV}}

V=\dfrac{h^2}{2q_em_e\lambda^2}

V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 9.1\times 10^{-31}\times (4.23\times 10^{-12})^2}

V=6.92\times 10^{34}\ V

V = 84109.27 volt

Hence, this is the required solution.

7 0
4 years ago
What compound makes wood
Luda [366]

Answer:lignin

Explanation:

4 0
3 years ago
How much water can be held by a cylindrical tank with a radius of 12 feet and a height of 30 feet? A. 2,260.8 cubic feet B. 13,5
MakcuM [25]

Answer:

Volume, V = 13564.8  cubic feet

Explanation:

It is given that,

Radius of the cylindrical tank, r = 12 feet

Height of the tank, h = 30 feet

We need to find the water that can be held by a cylindrical tank i.e. we need to find the volume of the tank. It is given by :

V=\pi\times r^2\times h

V=3.14\times (12)^2\times 30

V = 13564.8  cubic feet

So, the water held by the tank is 13564.8  cubic feet. Hence, this is the required solution.

6 0
3 years ago
PLEASE HELP ME TIMED TEST!!!
malfutka [58]

Answer:

56

Explanation:

I just want the points to be completely honest with you.  

7 0
3 years ago
Read 2 more answers
Gravity can be described as..?
Tju [1.3M]

Answer:

D

Explanation:

Gravity is the force of attraction between two objects.

Each object creates a gravitational field in wich every other object is affected by it.

6 0
4 years ago
Other questions:
  • What role does density play in the movement of convection curruents?
    5·1 answer
  • What is a factor that affects the outcome of an experiment?
    6·2 answers
  • Can anyone explain how to do this to me? It is due tomorrow at 9:30am. Thanks.
    8·1 answer
  • Which phrase most closely characterizes a person's sense of self?
    7·1 answer
  • Are materials that dissolve in water hydrophobic or hydrophilic
    7·2 answers
  • What is the longest wavelength in the molecule’s fluorescence spectrum?
    10·2 answers
  • I NEED HELP ASAP WILL MARK BRAINLIEST:
    5·1 answer
  • Whats potential energy?
    8·2 answers
  • A horizontal, mass spring system undergoes simple harmonic motion. which of the following statements is correct reguarding the m
    7·1 answer
  • Which best describes the difference between internal and thermal energy?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!