1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
timama [110]
2 years ago
15

A child is swinging back and forth on a swing. Changes in her kinetic and potential energy are happening each moment. At which p

oint, or multiple points, in her swinging would each of these two types of energy be at a maximum? In one to two sentences, describe these points and which type of energy is at a maximum at each point.(2 points)
plzz help
Physics
1 answer:
borishaifa [10]2 years ago
3 0

Answer:

There are two extreme points during the motion of child, where, the potential energy will be maximum due to maximum height.

there is one point, which is the mean position, where, the kinetic energy will be maximum due to maximum velocity.

Explanation:

FOR POTENTIAL ENERGY:

Since, the potential energy of the child depends upon the height of the child as follows:

P.E = mgh

where,

P.E = Potential Energy of Child

m = mass of child

g = acceleration due to gravity

h = height of child

<u>So, there are two extreme points during the motion of child, where, the potential energy will be maximum due to maximum height. </u>

<u></u>

FOR KINETIC ENERGY:

Since, the kinetic energy of the child depends upon the speed of the child as follows:

K.E = (1/2)mv²

where,

K.E = Kinetic Energy of Child

m = mass of child

v = velocity

<u>So, there is one point, which is the mean position, where, the kinetic energy will be maximum due to maximum velocity. </u>

<u></u>

You might be interested in
A burglar attempts to drag a 108 kg metal safe across a polished wood floor Assume that the coefficient of static friction is 0.
V125BC [204]

Answer:

2.00 m/s²

Explanation:

Given

The Mass of the metal safe, M = 108kg

Pushing force applied by the burglar,  F = 534 N

Co-efficient of kinetic friction, \mu_k = 0.3

Now,

The force against the kinetic friction is given as:

f = \mu_k N = u_k Mg

Where,

N = Normal reaction

g= acceleration due to the gravity

Substituting the values in the above equation, we get

f = 0.3\times108\times9.8

or

f = 317.52N

Now, the net force on to the metal safe is

F_{Net}= F-f

Substituting the values in the equation we get

 F_{Net}= 534N-317.52N

or

F_{Net}= 216.48

also,

 

F_{Net}= M\timesacceleration of the safe

Therefore, the acceleration of the metal safe will be

acceleration of the safe=\frac{F_{Net}}{M}

or

 acceleration of the safe=\frac{216.48}{108}

or

 

acceleration of the safe=2.00 m/s^2

Hence, the acceleration of the metal safe will be  2.00 m/s²

3 0
2 years ago
What is the name of the ratio of the voltage applied to a circuit and the current in a circuit
malfutka [58]
Resistance is the name of the ratio of the voltage applied to a circuit and the current in a circuit. Goes under <span>Ohm's Law</span>
4 0
3 years ago
A low-pass first-order instrument has a time constant of 20 ms. find the frequency, in hertz, of the input at which the output w
Vladimir [108]
?????????????????????????????
8 0
3 years ago
A man pulls a 10 kg box at constant speed across the floor with a rope. The tension in the rope is 120 N at an angle of 30°.
Murrr4er [49]

Answer:

98n

Explanation:

5 0
2 years ago
You observe a hockey puck of mass 0.12 kg, traveling across the ice at speed 18.3 m/sec. The interaction of the puck and the ice
Galina-37 [17]

The stopping distance is 143.1 m

Explanation:

First of all, we have to find the acceleration of the hockey puck. This can be done by using Newton's second law of motion:

\sum F =ma

where

\sum F = F_f = -0.14 N is the net force acting on the puck (the force of friction, negative because it acts in a direction opposite to the direction of motion)

m = 0.12 kg is the mass of the puck

a is the acceleration

Solving for a,

a=\frac{\sum F}{m}=\frac{-0.14}{0.12}=-1.17 m/s^2

The motion of the puck is a uniformly accelerated motion, therefore we can use the following suvat equation:

v^2-u^2=2as

where:

v = 0 is the final velocity (the puck comes to a stop)

u = 18.3 m/s is the initial velocity

a=-1.17 m/s^2 is the acceleration

s is the stopping distance

And solving for s, we find

s=\frac{v^2-u^2}{2a}=\frac{0-(18.3)^2}{2(-1.17)}=143.1 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

6 0
3 years ago
Other questions:
  • Mass is measured using _____.
    7·2 answers
  • 3. During a race, a sprinter increases from 5.0 m/s to 7.5 m/s over a period of 1.25s. What is the sprinter’s average accelerati
    9·1 answer
  • A manufacturer claims that a carpet will not generate more than 5.8 kV of static electricity What magnitude of charge would have
    6·1 answer
  • A normal mode of a closed system is an oscillation of the system in which all parts oscillate at a single frequency. In general
    11·1 answer
  • true or false temperature and precipitation are the two most important elements of climate for the majorit of living things
    11·1 answer
  • The large intestine ends in the ___.
    8·2 answers
  • Sully uses a battery and a coil of wire to create an electromagnet. Using the same materials, if he wants to increase the streng
    9·2 answers
  • A toy gun uses a spring to project a 4.5-g soft rubber sphere horizontally. The spring constant is 8.0 N/m, the barrel of the gu
    7·2 answers
  • The phases of the moon occur because the moon revolves around the earth.<br><br> True<br><br> False
    6·1 answer
  • In addition to ozone, what four other greenhouse gases or groups of greenhouse gases are included in nearly all the climate mode
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!