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DochEvi [55]
3 years ago
6

I WILL MARK BRAINLIEST!

Physics
1 answer:
Leokris [45]3 years ago
4 0

Answer:

I would say b) 3.1 second.

Explanation:

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For a centrifugal compressor, the flow at the exit of the blade (state 2) has a velocity of 250 m/s with an angle of 15 degrees
shtirl [24]

The velocity at the end of vaneless space(state 3) is  965.92 m/s

<h3>What is centrifugal compressor?</h3>

It increases kinetic energy to the airstream using a rotating element and then converts it into potential energy in the form of pressure.

Temperature at state 2, T₂ =T₀ + c/2Cp

Substitute T₀ =450K, c=250m/s, Cp =1005, we get

T₂ =418.90K

From the velocity triangle, sinβ₂ =c₂/v₂

v₂ = 250/sin (90°-75°) = 965.92 m/s

Thus, the velocity at the end of vaneless space is 965.92 m/s.

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3 years ago
Melanie watched the path a baseball followed after a pitcher threw it. She noticed that the ball traveled horizontally away from
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4 years ago
A 500 N weight is hung at the middle of a rope attached to two buildings at the same level. If the breaks in the tension exceed
Lyrx [107]

Not sure what you mean by "breaks in the tension" but I suspect you mean the rope will come apart if the tension in the rope exceeds 1800 N.

In the free body diagram for the 500 N weight, we have a figure Y with the net force equations

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• vertical net force:

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From the first equation, it follows that T₁ = T₂, so I'll denote their magnitude by T alone. From the second equation, we have

2 T sin(θ) = 500 N

and if the maximum permissible tension is T = 1800 N, it follows that

sin(θ) = (500 N) / (3600 N)   ⇒   θ = arcsin(5/36) ≈ 7.9°

is the smallest angle the rope can make with the horizontal.

6 0
3 years ago
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