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AlexFokin [52]
3 years ago
13

Acid rain occurs when sulfur dioxide in the atmosphere is oxidized in the presence of nitrogen dioxide. Acid rain is an example

of _______.a.a primary pollutantb.a secondary pollutantc.a tertiary pollutantd.none of the above Please select the best answer from the choices providedABCD
Chemistry
1 answer:
Bas_tet [7]3 years ago
8 0

Answer:

B. Secondary pollutant

Explanation:

A primary pollutant is directly emitted into the atmosphere. Volcano eruptions and emissions from cars can result in primary pollutants in the air.

Secondary pollutants are not directly put in the atmosphere. They are created when two or more primary pollutants in the atmosphere react. One example is smog.

Another example is acid rain. If sulphur dioxide, nitrogen dioxide and water react, then acid rain is formed. Therefore, acid rain must be a secondary pollutant.

The best answer choice is B. secondary pollutant

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Strong acids are assumed 100% dissociated in water. True As a solution becomes more basic, the pOH of the solution increases. Fa
Kruka [31]

Answer:

Strong acids are assumed 100% dissociated in water- True

As a solution becomes more basic, the pOH of the solution increases- false

The conjugate base of a weak acid is a strong base- true

The Ka equilibrium constant always refers to the reaction of an acid with water to produce the conjugate base of the acid and the hydronium ion- True

As the Kb value for a base increases, base strength increases- true

The weaker the acid, the stronger the conjugate base- true

Explanation:

An acid is regarded as a strong acid if it attains 100% or complete dissociation in water.

The pOH decreases as a solution becomes more basic (as OH^- concentration increases).

Ka refers to the dissociation of an acid HA into H3O^+ and A^-.

The greater the base dissociation constant, the greater the base strength.

The weaker an acid is, the stronger , its conjugate base will be.

7 0
3 years ago
When molten sulfur reacts with chlorine gas, a vile-smelling orange liquid forms that has an empirical formula of SCl. The struc
egoroff_w [7]

Answer:

The structure is shown below.

Explanation:

The formal charge (FC) is the charge that is more close to the actual charge in the real molecules and ions. It can be calculated based on the number of valence electrons (V), the shared electrons (S) and the electrons in the lone pairs (L) by the equation:

FC = V - (L + S/2)

Sulfur is in group 16 of the periodic table, so it has 6 valence electrons, and chlorine is from group 17 of the periodic table, and so it has 7 valence electrons. Chlorine can share only one electron, so it is stable. Sulfur can expand its octet (because it's from the third period) and can have more than 8 electrons when stable.

The possible formulas, from the empiric one, are:

SCl, S₂Cl₂, and S₃Cl₃.

To have FC = 0, chlorine must done only one bond, because S = 2, and L = 6, so:

FC = 7 - (6 + 2/2) = 0

So, it can not be the central atom of a structure. In the SCl, it will hav only a simple bond, so for sulfur, S = 2, and L = 4 (only the lone pairs are counted)

FC = 6 - (4+ 2/2) = +1

For S₂Cl₂, the two sulfurs must be bonded to a simple bond, and each one to one chlorine, thus, for both od them S = 4, and L = 4. so

FC = 6 - (4 + 4/2) = 0

So, it is the correct structure. The lewis structure represents the bonds by lines and the lone pairs of electrons by dots, and it is shown below.

3 0
3 years ago
How does an atom behave if it has a full octet of valence electrons?
erastova [34]

Answer:

A) Very stable.

Explanation:

A valence electron ring takes up to 8 valence electrons. If it has full rings, it is stable.

6 0
3 years ago
Read 2 more answers
If you want to determine the actual salicylate concentration for a sample that gives a greater absorption than the highest conce
Anarel [89]

Answer: The concentration of unknown sample is 1.8 mg/ml

Explanation:

According to the dilution law,

M_1V_1=M_2V_2

where,  

M_1 = concentration of stock solution = ?

V_1 = volume of stock solution = 0.25 ml  

M_1 = concentration of diluted solution = 0.45 mg/ml

V_1 = volume of diluted solution = (0.25+0.75) ml = 1.00 ml

Putting in the values we get:

M_1\times 0.25=0.45\times 1.00

M_1=1.8mg/ml

Therefore, concentration of unknown sample is 1.8 mg/ml

3 0
3 years ago
"calculate the h+ in a solution that has a ph of 8.73"
alexdok [17]
The  H+   in  a  solution  that  has  a Ph  of  8.73   is   calculate    as  follows

Ph is always =   -  log  (H+)

H+  =    10^-Ph

H+  is  therefore  =  10 ^-  8.73
H+  =  1.86  x10^-9  M
8 0
3 years ago
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