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Dvinal [7]
3 years ago
15

How many atoms of carbon are in diamond

Chemistry
1 answer:
Arada [10]3 years ago
4 0

Answer:

A diamond contains 5.0 x 10 21 atoms of carbon.

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Using the table on the right, complete each calculation by typing in the correct answer.
Pavel [41]

Answer:

13,200 mL

Explanation:

multiply by 1000 to go from L to mL

8 0
3 years ago
Explain why it is important to assume that the rate of radioactive decay aka radioactivity will remain constant over time?
marusya05 [52]

Answer and Explanation:

It's very important to assume that the rate of radioactive decay will remain constant over time to make scientists' lives easier when calculating the ages of fossils, compounds, etc.

If the rate changes, it would be extremely challenging for people to figure out the relative ages of rock strata, fossils, or other substances with radioactive elements in them. This is a fundamental assumption in order to be able to use radioactive dating.

Hope this helps!

8 0
4 years ago
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Plants that have nigrogen fixing bacteria in their roots are called​
iragen [17]

Plants that have nigrogen fixing bacteria in their roots are called​

legumes.

8 0
3 years ago
(e) Another student investigated the rate of a different reaction
vodka [1.7K]

Answer:

0.07 g/s.

Explanation:

From the question given above, the following data were obtained:

Mass lost = 9.85 g

Time taken = 2 min 30 s

Mean rate =?

Next, we shall convert 2 min 30 s to seconds (s). This can be obtained as follow:

1 min = 60 s

Thus,

2 min = 2 × 60 = 120 s

Therefore,

2 min 30 s = 120 s + 30 s = 150 s

Finally, we shall determine the mean rate of the reaction. This can be obtained as illustrated below:

Mass lost = 9.85 g

Time taken = 150 s

Mean rate =?

Mean rate = mass lost / time taken

Mean rate = 9.85 / 150

Mean rate = 0.07 g/s

Therefore, the mean rate of the reaction is 0.07 g/s

4 0
3 years ago
Which organisms are consumers?
masya89 [10]

Answer: snake grass hopper and monkey

Explanation: i took the test and this is what i got

8 0
3 years ago
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