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3 years ago

You have 500 mL of 5 M HCl already made. You need to dilute the solution to 1 M HCl. How much water will you need to add?

Chemistry

1 answer:

hram777 [196]3 years ago

5 0

Answer:

You need to add 400mL of water

Explanation:

500mL = 5 M HCI That means that if you divide both sides by 5

100mL = 1 M HCI If you need ot get rid of 4 M HCI then you add 400 mL of water because that is what it is equal to

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Get Organized! A Periodic Table WebQuest

netineya [11]

<h2>Answer:</h2>

What does Atomic number represents ___________.

What does the Mass number represent ___________

Periods are _____________ rows.

Groups are _____________ columns.

Total elements in periodic table are _____________.

5 0

4 years ago

Mary and her siblings share similar hair color. Which of these cell components are most involved in determining the hair color o

aksik [14]

The question is incomplete, the complete question is;

1. Mary and her siblings share similar hair color. Which of these cell components are most involved in determining the hair color of each sibling?

Gene, Chromosome, Nucleus

Cytoplasm, Chloroplasts,Genes

Vacuoles, Nucleus, Chromosomes

Chromosomes, Chloroplasts, Vacuoles

Answer:

Gene, Chromosome, Nucleus

Explanation:

Gene is defined in biology as "a unit of heredity which is transferred from a parent to offspring and is held to determine some characteristic of the offspring" (Oxford Dictionary).

The gene is located in the chromosomes in the nucleus of cells. The sum total of the genes that an organism inherits from its parents is called the organisms' genotype and determines certain features of the organism.

The hair colour of Mary and each of her siblings depends on the genes they received from their parents.

7 0

3 years ago

In the preparation of a certain alkyl halide, 10 g of sodium bromide (NaBr), 10 mL distilled water (H20), and 9 mL 3-methyl-1-bu

Novosadov [1.4K]

Percentage yield shows the amount of reactants converted into products. The percentage yield of the reaction is 51.7%.

The equation of the reaction is sown in the image attached. The reaction is 1:1 as we can see.

Number of moles of NaBr = 10 g/103 g/mol = 0.097 moles

We can obtain the mass of 3-methyl-1-butanol from its density.

Mass = density × volume

Density of 3-methyl-1-butanol = 0.810 g/mL

Volume of 3-methyl-1-butanol = 9 mL

Mass of 3-methyl-1-butanol = 0.810 g/mL × 9 mL

Mass of 3-methyl-1-butanol = 7.29 g

Number of moles of 3-methyl-1-butanol = mass/molar mass = 7.29 g/88 g/mol = 0.083 moles

Since the reaction is 1:1 then the limiting reagent is 3-methyl-1-butanol

Mass of product 1-bromo-3-methylbutane = number of moles × molar mass

Molar mass of 1-bromo-3-methylbutane = 151 g/mol

Mass of product 1-bromo-3-methylbutane = 0.083 moles × 151 g/mol

= 12.53 g

Recall that % yield = actual yield/theoretical yield × 100

Actual yield of product = 6.48 g

Theoretical yield = 12.53 g

% yield = 6.48 g/12.53 g × 100

% yield = 51.7%

Learn more: brainly.com/question/5325004

7 0

2 years ago

Which of the following would dissolve in water?<br> CCl4<br> LiCl<br> CH4<br> PCl6

babymother [125]

Like dissolves like
so water is polar

CCl4 is nonpolar
LiCl is polar
CH4 is nonpolar
PCl6 is nonpolar

so LiCl would dissolve

7 0

3 years ago

Read 2 more answers

Calculate the entropy change for the surroundings of the reaction below at 350K: N2(g) + 3H2(g) -> 2NH3(g) Entropy data: NH3

krek1111 [17]

Answer : The entropy change for the surroundings of the reaction is, -198.3 J/K

Explanation :

We have to calculate the entropy change of reaction $(\Delta S^o)$ .

$\Delta S^o=S_{product}-S_{reactant}$

$\Delta S^o=[n_{NH_3}\times \Delta S^0_{(NH_3)}]-[n_{N_2}\times \Delta S^0_{(N_2)}+n_{H_2}\times \Delta S^0_{(H_2)}]$

where,

$\Delta S^o$ = entropy of reaction = ?

n = number of moles

$\Delta S^0{(NH_3)}$ = standard entropy of $NH_3$

$\Delta S^0{(H_2)}$ = standard entropy of $H_2$

$\Delta S^0{(N_2)}$ = standard entropy of $N_2$

Now put all the given values in this expression, we get:

$\Delta S^o=[2mole\times (192.5J/K.mole)]-[1mole\times (191.5J/K.mole)+3mole\times (130.6J/K.mole)]$

$\Delta S^o=-198.3J/K$

Therefore, the entropy change for the surroundings of the reaction is, -198.3 J/K

4 0

3 years ago