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antiseptic1488 [7]
3 years ago
12

You have 500 mL of 5 M HCl already made. You need to dilute the solution to 1 M HCl. How much water will you need to add?

Chemistry
1 answer:
hram777 [196]3 years ago
5 0

Answer:

You need to add 400mL of water

Explanation:

500mL = 5 M HCI     That means that if you divide both sides by 5

100mL = 1 M HCI         If you need ot get rid of 4 M HCI then you add 400 mL of water because that is what it is equal to

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What are the two variables that affect the electric force between two objects?
givi [52]

Explanation:

The electrical force between two objects is given by the formula as follows :

F=\dfrac{kq_1q_2}{d^2}

k is electrostatic constant

q₁ and q₂ are electric charges

d is distance between charges

So, the two force between two charged objects depends on the product of charges and distance between charges.

5 0
2 years ago
Predict what will be observed in each experiment below. A student sees tiny bubbles clinging to the inside of an unopened plasti
Arisa [49]

Answer:

A.

Explanation:

Squeezing the bottle creates negative pressure inside the bottle because of the plastic's elasticity that will hasten the extraction of the carbon dioxide from the soda.

6 0
3 years ago
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For the reaction o(g) + o2(g) → o3(g) δh o = −107.2 kj/mol given that the bond enthalpy in o2(g) is 498.7 kj/mol, calculate the
Aneli [31]
The reaction;
O(g) +O2(g)→O3(g), ΔH = sum of bond enthalpy of reactants-sum of food enthalpy of products.
ΔH = ( bond enthalpy of O(g)+bond enthalpy of O2 (g) - bond enthalpy of O3(g)
-107.2 kJ/mol = O+487.7kJ/mol =O+487.7 kJ/mol +487.7kJ/mol =594.9 kJ/mol
Bond enthalpy (BE) of O3(g) is equals to 2× bond enthalpy of O3(g) because, O3(g) has two types of bonds from its lewis structure (0-0=0).
∴2BE of O3(g) = 594.9kJ/mol
Average bond enthalpy = 594.9kJ/mol/2
=297.45kJ/mol
∴ Averange bond enthalpy of O3(g) is 297.45kJ/mol.
8 0
3 years ago
What happens if a geologist drips a small amount of vinegar (acetic acid) onto a sample of dolomite?
Lapatulllka [165]
Hydrochloric acid on a rock or mineral and watching for bubbles of carbon dioxide gas to be released. The bubbles signal the presence of carbonate minerals such as calcite and dolomite.
4 0
3 years ago
The equilibrium: 2 NO2(g) \Longleftrightarrow⇔ N2O4(g) has Kc = 4.7 at 100ºC. What is true about the rates of the forwar
Sergeeva-Olga [200]

Answer:

  • Initial: forward rate > reverse rate
  • Equilibrium: forward rate = reverse rate

Explanation:

2NO₂(g) → N₂O₄(g)   Kc=4.7

The definition of <em>equilibrium</em> is when the forward rate and the reverse rate are <em>equal</em>.

Because in the initial state there's only NO₂, there's no possibility for the reverse reaction (from N₂O₄ to NO₂). Thus the forward rate will be larger than the reverse rate.

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