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antiseptic1488 [7]
3 years ago
12

You have 500 mL of 5 M HCl already made. You need to dilute the solution to 1 M HCl. How much water will you need to add?

Chemistry
1 answer:
hram777 [196]3 years ago
5 0

Answer:

You need to add 400mL of water

Explanation:

500mL = 5 M HCI     That means that if you divide both sides by 5

100mL = 1 M HCI         If you need ot get rid of 4 M HCI then you add 400 mL of water because that is what it is equal to

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AlexFokin [52]
With a pH of five, it would mean that this substance is a weak acid one would also it expect it would be sour.
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Can anyone please help with this!!
Sphinxa [80]

Answer:

2341, last option is the correct choice.

Explanation:

Boiling points of the given compounds are given as:

CH_4=-161.5\:C^{\circ}\\\\C_4H_{10}=-1\:C^{\circ}\\\\CH_2Cl_2=39.6\:C^{\circ}\\\\H_2O=100\:C^{\circ}

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Can someone plss help me with this question!!
Ivahew [28]

Answer:

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7 0
3 years ago
How important is the resonance structure shown here to the overall structure of carbon dioxide?
Tcecarenko [31]

1. Resonance structures are a better description of a Lewis dot structure .

2. Best resonance structure is the one with the least formal charge.


<u>EXPLAINATION OF RASONANCE STRUCTURE OF CARBON DIOXIDE</u>

1.Carbon dioxide has three resonance structures .

2. The CO2 molecule has a total of 16 valence electrons ,

  1C = 4 electrons

  2O= 12 electrons

<u>three resonance structures for  CO2</u>

1. The atoms in all three resonance structures have full octets;

 structure 1 will be more stable because it has no separation of charge.

2. Structures 2 and 3 show charge separation caused by the presence of formal charges on both oxygen atoms.  

6 0
3 years ago
Calculate the [OH-] and the pH of a solution with an [H+= .00083 M at 25 degrees
sesenic [268]
<h3>Answer:</h3>

1.2 × 10^-11 M

<h3>Explanation:</h3>

<u>We are given;</u>

Concentration of Hydrogen ions [H⁺] as 0.00083 M

<u>We are required to calculate the concentration of [OH⁻]</u>

We know that;

pH = - log [H⁺]

POH = -log[OH⁻]

Also, pH + pOH = 14

With the concentration of H⁺ we can calculate the pH

pH = -log 0.00083 M

    = 3.08

But; pH + pOH = 14

Therefore; pOH = 14 - pH

                           = 14 - 3.08

                          = 10.92

But, pOH = -log[OH⁻]

Therefore; [OH] = -Antilog(pOH)

Hence; [OH⁻] = Antilog -10.92

                     = 1.2 × 10^-11 M

Therefore, [OH⁻] is 1.2 × 10^-11 M

6 0
3 years ago
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