Answer:
How many items did Bob produce last week? 32 items.
Step-by-step explanation:
(1) Last week Bob was paid total of $480 for the items that he produced that week.
(2) This week Bob produced 2 items more than last week and was paid a total of $510 for the items that he produced this week.
a) Let's start with the simplest case: he produced 36 or less items this week.
In this case he produced less than 36 items last week too.
So he was paid the same amount of dollar per item.
Using (1) and (2) assumptions we have:
$480+2X=$510
⇒2X=$510-$480
⇒2X=$30
⇒2X=$30/2
⇒X=$15
He was paid $15 per item.
Last week he was paid $480.
480/15= 32 items.
This week he was paid $510.
510/15=34 items.
The other cases has no solutions.
Answer:
x=150
Step-by-step explanation:
x+30=180[co-interior angle]
x=180-30
x=150
<em>Option 2 </em>
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It's just the black part and the empty square under which is 1/2 and the red square with the empty square under is 1/2 so it's 1/2 x 1/2
Call the smaller of the two odds = n
Call the next number in the sequence = n + 2
n*(n +2) = 782 Remove the brackets.
n^2 + 2n = 782 Subract 782 from both sides.
n^2 + 2n - 782 = 0 We are going to have to factor this.
Discussion
This problem can't be done the way it is written. The product of an odd integer with another odd integer is and odd integer. There are no exceptions to this. So you need to give a number that has two factors very near it's square root for this question to work.
For example, you could use 783, (which factors) instead of 782 .
Solve
n^2 + 2n - 783 = 0
(n + 29)(x - 27) = 0
<u>Solution One</u>
n - 27 = 0
n = 27
The two odd consecutive integers are 27 and 29.
<u>Solution Two</u>
n + 29 = 0
n = - 29
The two solution integers are -29 and - 27 Notice that - 29 is smaller than - 27.
7 3/10 + 6 1/3 + 2 7/10
First change them to improper fractions
73/10 + 19/3 + 27/10
now find the common denominator which would be 30
73/10 = 219 /30
19/3 = 190/30
27/10 = 81 /30
now add (219 + 190 + 81) = 490/30
now divide 490 ÷ 30 = 16 1/3
Your answer is 16 1/3
Hope this helps. :)
