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4vir4ik [10]
4 years ago
8

Mr.nguyen decides to walk to school. How long does it take him to walk 10000m if he is traveling with a constant velocity of 2m/

s?
Physics
1 answer:
exis [7]4 years ago
8 0

Answer:

5000 s

Explanation:

Mr. Nguyen is moving in uniform motion (constant speed), therefore the distance he covers is given by the equation:

d=vt

where

d is the distance

v is the speed

t is the time taken

Here we have

d = 10000 m

v = 2 m/s

Solving for t, we find the time taken to cover this distance:

t=\frac{d}{v}=\frac{10000}{2}=5000 s

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A horizontal circular platform (m = 119.1 kg, r = 3.23m) rotates about a frictionless vertical axle. A student (m = 54.3kg) walk
Murrr4er [49]

Answer:

\omega_2=5.1rad/s

Explanation:

Since there is no friction angular momentum is conserved. The formula for angular momentum thet will be useful in this case is L=I\omega. If we call 1 the situation when the student is at the rim and 2 the situation when the student is at r_2=1.39m from the center, then we have:

L_1=L_2

Or:

I_1\omega_1=I_2\omega_2

And we want to calculate:

\omega_2=\frac{I_1\omega_1}{I_2}

The total moment of inertia will be the sum of the moment of intertia of the disk of mass m_D=119.1 kg and radius r_D=3.23m, which is I_D=\frac{m_Dr_D^2}{2}, and the moment of intertia of the student of mass m_S=54.3kg at position r (which will be r_1=r=3.23m or r_2=1.39m) will be I_{S}=m_Sr_S^2, so we will have:

\omega_2=\frac{(I_D+I_{S1})\omega_1}{(I_D+I_{S2})}

or:

\omega_2=\frac{(\frac{m_Dr_D^2}{2}+m_Sr_{S1}^2)\omega_1}{(\frac{m_Dr_D^2}{2}+m_Sr_{S2}^2)}

which for our values is:

\omega_2=\frac{(\frac{(119.1kg)(3.23m)^2}{2}+(54.3kg)(3.23m)^2)(3.1rad/s)}{(\frac{(119.1kg)(3.23m)^2}{2}+(54.3kg)(1.39m)^2)}=5.1rad/s

6 0
3 years ago
Alguém tem a resposta ?
Maru [420]
The answer is D or C
3 0
3 years ago
You take a Frisbee to the top of the Washington Monument and send it sailing along horizontally at a speed of 5 m/s from the ver
Dominik [7]

This question can be solved with the help of the equations of motion.

A) The Frisbee will remain in the air for "5.87 s".

B) The frisbee will go "29.4 m" down the range.

A)

To calculate the time, the frisbee will remain in the air, we will use the second <em><u>equation of motion</u></em>, for the vertical motion.

h = v_it+\frac{1}{2}gt^2\\\\

where,

h = height = 169.2 m

vi = initial velocity's vertical component = 0 m/s

g = acceleration due to gravity = 9.81 m/s²

t = time = ?

Therefore,

169.2\ m = (0\ m/s)(t)+\frac{1}{2}(9.81\ m/s^2)t^2\\\\t = \sqrt{\frac{(169.2\ m)(2)}{9.81\ m/s^2}}

<u>t = 5.87 s</u>

<u />

B)

Now, we will calculate the horizontal range by applying the equation for constant motion. Because the velocity in the horizontal direction will remain constant due to no air resistance

s = vt

where,

s = horizontal range = ?

v= initial velocity's horizontal component = 5 m/s

t = time = 5.87 s

Therefore,

s = (5 m/s)(5.87 s)

<u>s = 29.4 m</u>

<u />

Learn more about <em><u>equations of motion</u></em> here:

brainly.com/question/9772550?referrer=searchResults

8 0
3 years ago
Who invented the first practical incandescent light bulb?.
OverLord2011 [107]

Answer:

Edison

Explanation:

Among other notable inventions, Edison and his assistants developed the first practical incandescent lightbulb in 1879 and a forerunner of the movie camera and projector in the late 1880s.

6 0
3 years ago
In which device is chemical energy transformed into electrical energy?
ehidna [41]

Answer:

A) Battery

Explanation:

A Battery because it holds lithium whatever stuff and we can use to power our electronics (Chemical -> electrical)

Hair dryers (electrical-> kinetic)

Television ( Electrical -> ???)

Hydroelectric plant ( Kinetic -> electrical)

4 0
3 years ago
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