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Damm [24]
2 years ago
10

Question 3 of 10

Physics
1 answer:
Ahat [919]2 years ago
3 0

Answer:

The unit of power is pascal.

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A girl weighing 600 N steps on a bathroom scale that contains a stiff spring. In equilibrium, the spring is compressed 1.0 cm un
8_murik_8 [283]

Answer:

The spring constant is 60,000 N

The total work done on it during the compression is 3 J

Explanation:

Given;

weight of the girl, W = 600 N

compression of the spring, x = 1 cm = 0.01 m

To determine the spring constant, we apply hook's law;

F = kx

where;

F is applied force or weight on the spring

k is the spring constant

x is the compression of the spring

k = F / x

k = 600 / 0.01

k = 60,000 N

The total work done on the spring = elastic potential energy of the spring, U;

U = ¹/₂kx²

U = ¹/₂(60000)(0.01)²

U = 3 J

Thus, the total work done on it during the compression is 3 J

3 0
3 years ago
A student uses an electronic force sensor to study how much force the student’s finger can apply to a specific location. The stu
melisa1 [442]

Answer:

B. Trial 2

Explanation:

Trial 2, because the student’s finger applied the largest force to the sensor.

Because the trial 2 student finger applied to largest force.

7 0
3 years ago
Read 2 more answers
The planet Gallifrey has 2 times the gravitational field strength and 2 times the radius of the Earth.
Alexeev081 [22]

The mass of the planet Gallifrey is 8 times the mass of the Earth.

  • let the gravitational field of Earth = g
  • let the radius of the Earth = R
  • gravitational field of Gallifrey = 2g
  • radius of Gallifrey = 2R

<h3>What is gravitational potential energy?</h3>
  • This is the work done in moving an object to a certain distance against gravitational field.

The gravitational field strength of the Earth is given as follows;

g = \frac{GM}{r^2} \\\\G = \frac{gr^2}{M}

The gravitational field strength of the Planet Gallifrey is calculated as follows;

g_2 = \frac{GM_2}{r_2^2}

G = \frac{g_2r_2^2}{M_2} \\\\\frac{g_2r_2^2}{M_2} = \frac{gr^2}{M}\\\\M_2gr^2 = Mg_2r_2^2\\\\M_2 = \frac{Mg_2r_2^2}{gr^2} \\\\M_2 = \frac{M \times 2g \times (2r)^2}{gr^2} \\\\M_2 = \frac{M \times 2g \times 4r^2}{gr^2} \\\\M_2 = 8M

Thus, the mass of the planet Gallifrey is 8 times the mass of the Earth.

Learn more about gravitational field strength here:  brainly.com/question/14080810

4 0
2 years ago
Suppose that the process were repeated, except that in step 3 a neutral acrylic rod instead of a finger is used to touch the ele
Marta_Voda [28]

Answer:

b) True Only if the finger is isolated from ground

c) True. The total charge does not change since the system is isolated

Explanation:

When the electroscope is touched with an acrylic rod, some charges are transferred from the electroscope to the rod, until the charge in both is equal.

In the case it know when the electroscope is touched with a finger, two things can happen.

- The body is isolated from the ground, the efective charge is redistributed between the two bodies. Case similar to insulating rod

- The body is connected to ground, the charge is transferred to the finger and from here to the ground until the total charge is transferred and the Earth and the final charge of the electroscope is zero.

Let's review the final statements

a) False, when part of the load is touched, it passes to the rod, so when it separates it does not return to the initial load

b) True Only if the finger is isolated from ground

c) True. The total load does not change since the system is isolated

d) False. The value of the load changes =, but its sign does not

8 0
3 years ago
A bird accelerating from rest at a constant rate,experiences a displacement of 28 m in 11s.What is its acceleration
Ksenya-84 [330]
Use the formula below for this question:

v_{f} = v_{i} + 2 * a * d

re-arrange to solve for a:

a = \frac{v_{f} - v_{i}}{2 * d}

now simply plug in your variables and there's your answer :). If you ever get stuck, you can look up the kinematic equations!
4 0
3 years ago
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