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Luden [163]
3 years ago
8

What's the difference and similarity between O2 and 2 O ?

Physics
1 answer:
nasty-shy [4]3 years ago
4 0
O2 refers to two oxygen atoms bonded together, while 2 O refers to two oxygen atoms that are not bonded to each other. They both have two oxygen atoms, but in O2, the oxygen atoms are bonded, while in 2O, the atoms are not.
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What does "Time (s)” represent in the graph? the y-axis the dependent variable an inverse relationship the independent variable
san4es73 [151]
Independent, and inverse means if one variable increases then the other decreases, direct is when they both go up or down together.
6 0
3 years ago
Read 2 more answers
How would this affect the electrostatic force between them?
Alja [10]

The answer is increase

Explanation:

6 0
3 years ago
A motorbike is traveling to the left with a speed of 27.0 m s 27.0 s m ​ 27, point, 0, start fraction, start text, m, end text,
Neporo4naja [7]

Answer:

Explanation:

Initial velocity , u = 27 m/s

displacement before stop,  s = 41.5 m .

final velocity,  v = 0

acceleration a = ?

v² = u² + 2 a s

0 = 27² + 2 x a x 41.5

a = - 27² / 2 x 41.5

= - 8.78 m /s

7 0
3 years ago
A car goes around a curve of radius 60 m at a constant speed of 15 m/s. Which of the following values is the centripetal acceler
IRISSAK [1]

Answer:

3.75 m/s^2

Explanation:

The centripetal acceleration of an object in uniform circular motion is given by the equation:

a=\frac{v^2}{r}

where

v is the tangential speed of the object

r is the radius of the trajectory

In this problem, r = 60 m and v = 15 m/s, therefore the centripetal acceleration of the car is

a=\frac{(15 m/s)^2}{60 m}=3.75 m/s^2

4 0
3 years ago
What is the frequency of a wave with speed 3m/s and wavelength 6m?
Korolek [52]

The frequency of the radio wave is

1

×

10

8

H

z

Explanation:

Let's use the this formula:

C

=

λ

×

v

C represents the speed of light, which has a value of approximately

3.00

×

10

8

m

s

λ

represents the wavelength and the units should be in meters.

v represents the frequency, which should have units of

H

z

or

s

−

1

. Hz is hertz or reciprocal seconds.

Now let's rearrange the equation to solve for v:

C

λ

=

v

v

=

3.00

×

10

8

m

s

/

(

3

m

)

=

1

×

10

8

s

−

1The frequency of the radio wave is

1

×

10

8

H

z

Explanation:

Let's use the this formula:

C

=

λ

×

v

C represents the speed of light, which has a value of approximately

3.00

×

10

8

m

s

λ

represents the wavelength and the units should be in meters.

v represents the frequency, which should have units of

H

z

or

s

−

1

. Hz is hertz or reciprocal seconds.

Now let's rearrange the equation to solve for v:

C

λ

=

v

v

=

3.00

×

10

8

m

s

/

(

3

m

)

=

1

×

10

8

s

−

1The frequency of the radio wave is

1

×

10

8

H

z

Explanation:

Let's use the this formula:

C

=

λ

×

v

C represents the speed of light, which has a value of approximately

3.00

×

10

8

m

s

λ

represents the wavelength and the units should be in meters.

v represents the frequency, which should have units of

H

z

or

s

−

1

. Hz is hertz or reciprocal seconds.

Now let's rearrange the equation to solve for v:

C

λ

=

v

v

=

3.00

×

10

8

m

s

/

(

3

m

)

=

1

×

10

8

s

−

1The frequency of the radio wave is

1

×

10

8

H

z

Explanation:

Let's use the this formula:

C

=

λ

×

v

C represents the speed of light, which has a value of approximately

3.00

×

10

8

m

s

λ

represents the wavelength and the units should be in meters.

v represents the frequency, which should have units of

H

z

or

s

−

1

. Hz is hertz or reciprocal seconds.

Now let's rearrange the equation to solve for v:

C

λ

=

v

v

=

3.00

×

10

8

m

s

/

(

3

m

)

=

1

×

10

8

s

−

1

3 0
2 years ago
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