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IrinaVladis [17]
3 years ago
7

Find the orbital speed v for a satellite in a circular orbit of radius R.Express the orbital speed in terms of G, M, and R.

Physics
1 answer:
AlekseyPX3 years ago
5 0
<h2>Answer:V=\sqrt{G\frac{M}{R}}  </h2>

The velocity of a satellite describing a circular orbit is <u>constant</u> and defined by the following expression:

V=\sqrt{G\frac{M}{R}}     (1)

Where:

G is the gravity constant

M the mass of the massive body around which the satellite is orbiting

R the radius of the orbit (measured from the center of the planet to the satellite).

Note this orbital speed, as well as orbital period, does not depend on the mass of the satellite. I<u>t depends on the mass of the massive body.</u>

In addition, this orbital speed is constant because at all times <u>both the kinetic energy and the potential remain constant</u> in a circular (closed) orbit.

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could anyone determinate the period knowing that it performs 4000 vibrations in 0.5 minutes, Sorry my english is bad
dexar [7]

Answer:

f = 4000 / 30 sec = 133.3    vibrations/sec

P = 1 / f = .0075 sec       period of 1 vibration

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2 years ago
E. weight = mass x gravitational field strength
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Answer:

e. weight = mass x gravitational field strength

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When running a marathon what kind of energy transformation takes place
xz_007 [3.2K]
Thermal energy is transforming, i think.
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3 years ago
An aquarium open at the top has 30-cm-deep water in it. You shine a laser pointer into the top opening so it is incident on the
Setler [38]

Answer:

You must add 8cm of water to the tank

Explanation:

In order to find how much the height is we will use the Snell Refraction law

.

This law relates the index of refraction of the water (n2), the index of refraction of the air (n1), the incidence angle relative to the vertical (theta1) and the refraction angle relative to the vertical (theta2) by using the next equation:

(n1)*(sin(theta1))=(n2)*(sin(theta2))

Then we will find the refraction angle relative to the vertical this way:

(n1/n2)*(sin(theta1))=sin(theta2)

(1/1.33)*(sin(45))=sin(theta2)

Then, theta2=32.12°

Now that we have this information we can imagine a triangle with a 30cm height and a 32.12° angle. This way we can find how much X is, this X will be the distance between the vertical line and the spot the beam hits the bottom, so we can use some trigonometry to find it, this way:

tan(32.12)=(X/30cm)

X=(tan(32.12))*(30cm)

Then, X=18.8cm, we can approximate it to 19cm

Once we have X we will add 5cm to it which is how much the beam needs to be moved, then the new X will be 24cm

Now, with the new horizontal distance we will find the new vertical distance, let´s call it Y, this way we will know how much water we must add to move the beam, then we will have a triangle with a vertical distance called Y, the same 32.12° angle will be used as we are still working with the air-water interface and a 19cm horizontal distance, then:

tan(32.12)=(24cm/Y)

Y=(24cm/tan(32.12))

Then, Y=38cm

In this case, you must add 8cm of water to the tank to move the beam on the bottom 5cm

5 0
3 years ago
The difference in a brass rod and steel rod is same as 12cm at all temperature .Find the length of the rod at 0°C.​
egoroff_w [7]

Answer:

I think its 12 cm itself. Because in the question it is said that the length is same in all temperature

5 0
2 years ago
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