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Anton [14]
4 years ago
8

What type of reaction does this equation represent? 2I4O9(s) → 4I2(s) + 9O2(g)

Chemistry
1 answer:
DIA [1.3K]4 years ago
6 0
This type of reaction is a decomposition reaction, where a starting compound breaks, or decomposes, into two or more different compounds.
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Determine the molarity of 56.00 grams of aluminum nitrate in 450 milliliters of solution?
SVETLANKA909090 [29]

Answer:

4.62 M

Explanation:

Molarity = moles/volumes (L), so you need to find the moles and the volumes in liters.

Finding the volume is easy because you just have to convert mL to L, so the volume is 0.45 L

Next, find the moles. You can do this by using the molar mass of aluminum to convert the grams to moles. The molar mass of aluminum is 26.98 g/mol.

56 g * (1 mol/26.98 g) = 2.08 mol

Now, divide the moles (2.08) by the volume (.45 L)

Molarity = 4.62 M

3 0
3 years ago
Why do you think different liquids have different freezing points
Ganezh [65]
I think that different liquids have different freezing points because every liquid consists of different atoms and different things that make up the atom causing them to have different freezing points.
5 0
3 years ago
Period, block, and group
Sedaia [141]

Answer:

what do you mean

Explanation:

8 0
3 years ago
What is the role of a consumer in the flow of energy through a food chain?
pogonyaev

Answer:

The role of consumers in an ecosystem is to obtain energy by feeding on other organisms and sometimes transfer energy to other consumers. Changes that affect consumers can impact other organisms within the ecosystem.

Explanation:

Hope this helped Mark BRAINLIEST!!!!

4 0
3 years ago
There are two naturally occurring isotopes of boron. 10 B has a mass of 10.0129 u. 11 B has a mass of 11.0093 u. Determine the a
Vanyuwa [196]
<h2>Natural Abundance for 10B is 19.60%</h2>

Explanation:

  • The natural isotopic abundance of 10B is 19.60%.
  • The natural isotopic abundance of 11B is 80.40%.
  • The isotopic masses of boron are 10.0129 u and 11.009 u respectively.

For calculation of abundance of both the isotopes -

Supposing it was 50/50, the average mass would be 10.5, so to increase the mass we need a more percentage of 11.

Determining it as an equation -

10x + 11y= 10.8

x+y=1 (ratio)

10x + 10y = 10

By taking the denominator away from the numerator

we get;

y = 0.8

x + y = 1

∴ x = 0.2

To get percentages  we need to multiply it by 100

So, the calculated abundance is 80% for 11 B and 20% 10  B.

5 0
3 years ago
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