The answer is 4! Hope this Helps
H₂S
<h3>Further explanation</h3>
Given
ΔH fusion and ΔH vaporization of different substances
Required
The substance absorbs 58.16 kJ of energy when 3.11 mol vaporizes
Solution
We can use the formula :

Q=heat/energy absorbed
n = moles
The heat absorbed : 58.16 kJ
moles = 3.11
so ΔH vaporization :

The correct substance which has ΔH vaporization = 18.7 kj / mol is H₂S
(H₂S from the data above has ΔH fusion = 2.37 kj / mol and ΔH vaporization = 18.7 kj / mol)
Answer:
Q = 10.10059 KJ
Explanation:
Given data:
Amount of water = 13.0 g
Initial temperature = 52.5°C
Final temperature = 238.2°C
Heat required to convert it into steam = ?
Solution:
Specific heat capacity of water is 4.184 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 238.2°C - 52.5°C
ΔT = 185.7 °C
by putting values,
Q = 13.0 g × 4.184 J/g.°C × 185.7 °C
Q = 10100.59 J
Jolue to Kj:
10100.59j × 1 KJ/1000 J
Q = 10.10059 KJ