Energy is carried to earth in _____?
2 answers:
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Answer:
The velocity of the ball is 3.52 m/s.
Explanation:
A projectile is any object that moves under the influence of gravity and momentum only. Examples are; a thrown ball, a fired bullet, a kicked ball, thrown javelin, etc.
Given that the ball was thrown vertically upward on the top of a skyscraper of height 61.9 m. So that the velocity can be determined by;
u =
Where: u is the velocity of the object, H is the height and g is the gravitational force on the object. Given that: H = 61.9 m and g = 10 m/, then;
u =
=
u = 3.5185
The velocity of the ball is 3.52 m/s.
Answer:
The ball rolled a distance of 54 m.
Explanation:
Given:
Initial velocity of the ball is,
Final velocity of the ball is,
Time for rolling is,
The distance of rolling is,
First, let us find the acceleration of the ball using Newton's equation of motion as:
Now, displacement of the ball can be determined using the following equation of motion:
Rewriting the above in terms of 'S', we get
Plug in the known values and solve for 'S'. This gives,
Therefore, the ball rolled a distance of 54 m.