Answer:
Explanation:
When an moving electric charge passes through a uniform magnetic field
its motion becomes circular .
If m be the mass v be the velocity , q be the charge on the mass B be the magnetic field and R be the radius of circular path
force on the moving charge created by magnetic field
= B q v
Centripetal force required for circular motion
= m v² / R
For balancing
B q v = m v² / R
v = B q R / m
Time period of rotation
T = 2π R / v
= 2 π R m / B q R
= 2 π m / B q
For first particle
T₁ = 2 π m₁ / B q₁
For second particle
T₂ = 2 π m₂ / B q₂
q₁ = q₂ and 10 m₁ = m₂ ( given )
Putting the values in second equation
T₂ = 2 π 10 m₁ / B q₁
= 10 x 2 π m₁ / B q₁
= 10 T₁
Given T₁ = T
T₂ = 10 T
<span>newton say that she must use her hand to put up the cup because the work is equal to force times it distance, that is in the same direction of the force applied. if carole used her hand to put up the cup, then he is not applying any work because the displacement is not in the same direction of the force</span>
Answer:
the phenomenon whereby a pair of particles are generated in such a way that the individual quantum states of each are indefinite until measured, and the act of measuring one determines the result of measuring the other, even when at a distance from each other.
Answer:
1/2m or 0.5m
Explanation:
The formula to find the speed of a wave is given by:
V = frequency x wavelength
To find the wavelength, make the wavelength the subject of the formula
Therefore, wavelength = velocity ÷ frequency
Answer:
F= 4788 N
Explanation:
Because the car moves with uniformly accelerated movement we apply the following formula:
vf²=v₀²+2*a*d Formula (1)
Where:
d:displacement in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
Data
d=36.9 m
v₀=14.0 m/s m/s
vf= 0
Calculating of the acceleration of the car
We replace dta in the formula (1)
vf²=v₀²+2*a*d
(0)²=(14)²+2*a*(36.9)
-(14)²= (73.8) *a
a= - (196) / (73.8)
a= - 2.66 m/s²
Newton's second law of the car in direction horizontal (x):
∑Fx = m*ax Formula (2)
∑F : algebraic sum of the forces in direction x-axis (N)
m : mass (kg)
a : acceleration (m/s²)
Data
m=1800 Fkg
a= - 2.66 m/s²
Magnitude of the horizontal net force (F) that is required to bring the car to a halt in a distance of 36.9 m :
We replace data in the formula (2)
-F= (1800 kg) * ( -2.66 m/s²
)
F= 4788 N
