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Ilia_Sergeevich [38]
3 years ago
6

Identify the compounds that are soluble in both water and hexane.

Chemistry
1 answer:
dlinn [17]3 years ago
3 0

Answer:

The compound which are boh soluble in water and hexane is

B. Ethanol and 1-propanol  

Explanation:

The compounds ethanol and 1-propanol are soluble in both hexane and water.

It is soluble in water as both  consists of polar end due to hydrogen bonding present in the  -OH functional group.

and both are soluble in hexane as they contain a non polar end and the alliphatic hydrocarbon chain in them.

The solubility of alcohols varies in increasing order as the hydrocarbon chain increases. And becaue of this it becomes more non polar.

Non polar properties decreases for branched molecules.

so, the correct option is ethanol and 1-propanol.

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<h3>1</h3>

Species shown in bold are precipitates.

  • Ca(NO₃)₂ + 2 KOH → Ca(OH)₂ + 2 KNO₃
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<h3>2</h3>

A double replacement reaction takes place only if it reduces in the concentration of ions in the solution. For example, the reaction between Ca(NO₃)₂ and KOH produces Ca(OH)₂. Ca(OH)₂ barely dissolves. The reaction has removed Ca²⁺ and OH⁻ ions from the solution.

Some of the reactions lead to neither precipitates nor gases. They will not take place since they are not energetically favored.


<h3>3</h3>

Compare the first and last row:

Both Ca(NO₃)₂ and Zn(NO₃)₂ react with KOH. However, between the two precipitates formed, Ca(OH)₂ is more soluble than Zn(OH)₂.

As a result, add the same amount of KOH to two Ca(NO₃)₂ and Zn(NO₃)₂ of equal concentration. The solution that end up with more precipitate shall belong to Zn(NO₃)₂.


<h3>4</h3>

Compare the second and third row:

Cu(NO₃)₂ reacts with KI, but Ni(NO₃)₂ does not. Thus, add equal amount of KI to the two unknowns. The solution that forms precipitate shall belong to Cu(NO₃)₂.

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