Explanation:
Family is usually considered to be the most important agent of socialization. They not only teach us how to care for ourselves, but also give us our first system of values, norms, and beliefs. ... Another agent of socialization that relates to school is our peer group.
The complete question is as follows: Barium chloride (BaCl2) emits a green color when flame tested. What can be said about the wavelength of light it emits? Select all that apply.
A) The thermal energy is transferred to the outer electrons of the barium ions.
B) The electrons gain enough energy to excite them to a higher energy level.
C) The electrons drop back down to their ground state, gaining energy.
D) The electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.
Answer: The following can be said about the wavelength of light that Barium chloride emits:
- The thermal energy is transferred to the outer electrons of the barium ions.
-
The electrons gain enough energy to excite them to a higher energy level.
- The electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.
Explanation:
As barium chloride is emitting green color when flame tested. This means that thermal energy is being transferred to the outer electrons of barium ions.
A visible light is emitted by a substance when its electrons move from a region of higher energy level to lower energy level. This is because energy is given off by the electrons when they move in a lower region.
This is only possible when the electrons gain enough energy to excite them to a higher energy level.
Also, the electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.
Thus, we can conclude that following can be said about the wavelength of light that Barium chloride emits:
- The thermal energy is transferred to the outer electrons of the barium ions.
-
The electrons gain enough energy to excite them to a higher energy level.
- The electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.
Answer:
The three naturally-occurring isotopes of hydrogen. The fact that each isotope has one proton makes them all variants of hydrogen: the identity of the isotope is given by the number of protons and neutrons. From left to right, the isotopes are protium (1H) with zero neutrons, deuterium (2H) with one neutron, and tritium (3H) with two neutrons.
The term isotope is formed from the Greek roots isos (ἴσος "equal") and topos (τόπος "place"), meaning "the same place"; thus, the meaning behind the name is that different isotopes of a single element occupy the same position on the periodic table.[2] It was coined by a Scottish doctor and writer Margaret Todd in 1913 in a suggestion to chemist Frederick Soddy.
The number of protons within the atom's nucleus is called atomic number and is equal to the number of electrons in the neutral (non-ionized) atom. Each atomic number identifies a specific element, but not the isotope; an atom of a given element may have a wide range in its number of neutrons. The number of nucleons (both protons and neutrons) in the nucleus is the atom's mass number, and each isotope of a given element has a different mass number.
For example, carbon-12, carbon-13, and carbon-14 are three isotopes of the element carbon with mass numbers 12, 13, and 14, respectively. The atomic number of carbon is 6, which means that every carbon atom has 6 protons, so that the neutron numbers of these isotopes are 6, 7, and 8 respectively.
When we have this equation:
CO(g) + Cl2(g) ↔ COCl2(g)
intial 0.147 0.175 0
change -X -X +X
final (0.147-X) (0.175-X) X
so from the ICE table, we substitute in Kc formula :(when we have Kc = 255)
Kc = [COCl2]/[CO][Cl2]
255= X / (0.147-X)(0.175-X)
255 = X / (X^2 - 0.322 X + 0.025725)
X = 0.13
∴[CO] = 0.147 - X = 0.147 - 0.13
= 0.017 m
<u>Answer:</u> The percent concentration ( % m/v) of dextrose in the solution is 2 %
<u>Explanation:</u>
We are given:
Mass of Yeast Extract = 5.0 grams
Mass of 
= 1.0 grams
Mass of 
= 0.5 grams
Mass of Dextrose = 20.0 grams
Mass of 
= 10. grams
Mass of Agar = 18.0 grams
Volume of solution = 1 L = 1000 mL (Conversion factor: 1 L = 1000 mL)
% (m/v) is defined as the concentration, which is mass of solute present in 100 mL of solution
To calculate the mass of solute, we apply unitary method:
In 1000 mL of solution, the mass of dextrose present is 20.0 grams
So, in 100 mL of solution, the mass of dextrose present will be = 
Calculating the % (m/v) of dextrose, we get:
Hence, the percent concentration ( % m/v) of dextrose in the solution is 2 %
