1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sedbober [7]
1 year ago
9

A student investigated the factors that affect math grades. Which statement from the lab report best represents a conclusion for

this investigation?

Chemistry
1 answer:
joja [24]1 year ago
7 0

The correct answer choice from the statement above about investigated factors from lab results is :

Students who spend less time studying after school get lower math grade

Option D is the correct answer

<h3>What is mathlab?</h3>

This is an online platform where mathematics tutors help students to solve their difficulties in mathematics.

Mathematics is one of the most important aspect of knowledge in the education.

So therefore, The correct answer choice from the statement above about investigated factors from lab results is :

Students who spend less time studying after school get lower math grade

Learn more about MathLab:

brainly.com/question/13974197

#SPJ1

You might be interested in
What volume would be needed to prepare 375 mL of a .45 M CaCl2 using only a solution of 1.0 M CaCl2 and water?
Neporo4naja [7]

Answer:

168.75 ml

Explanation:

M1V1=M2V2

375ml*.45M=1M*V2

8 0
3 years ago
38) Which of the following is not a reaction of alcohol
mylen [45]
<h2>I guess...</h2>

<h3>Dehydration </h3>
8 0
3 years ago
1 mol super cooled liquid water transformed to solid ice at -10 oC under 1 atm pressure.
Arada [10]

Answer:

Explanation:

Given that:

number of moles of super cooled liquid water = 1

Melting enthalpy of ice = 6020 J/mol

Freezing point =0 °C = (0 + 273 K)= 273 K

The decrease in entropy of the system during freezing for 1 mol (i.e during transformation from liquid water to solid ice )  = - 6020 J/mol × 1 mol /273 K = -22.051 J/K

Entropy change during further cooling from 0 °C (273 K) to -10 °C (263 K)

\Delta \ S = \int\limits^{T_2}_{T_1}\dfrac{nC_p(s)dT}{T}

\Delta \ S = {nC_p(s)In \dfrac{T_2}{T_1}

\Delta \ S = {(1*37.7)In \dfrac{263}{273}

Δ S = -1.4 J/K

Total entropy change of the system = - 22.05 J/K - 1.4 J/K = - 23.45 J/K

Entropy change of universe = entropy change of the system+ entropy change of the surrounding

According to the second law of thermodynamics

Entropy change of universe  >0

SO,

Entropy change of the system + entropy change in the surrounding > 0

Entropy change in the surrounding > - entropy change of the system

Entropy change in the surrounding > - (- 23.53 J/K)

Entropy change in the surrounding > 23.53 J/K

b) Make some comments on entropy changes from the obtained data.

From the data obtained; we will realize that the entropy of the system decreases as cooling takes place when water is be convert to ice , randomness of these molecules reduces and as cooling proceeds , hence, entropy reduces more as well and the liberated heat will go into the surrounding due to this entropy of the surrounding increasing.

4 0
3 years ago
One disadvantage of burning propane (C3H8) is that carbon dioxide is one of the products. The released CO2 increases the growing
Hoochie [10]

Answer:

80 MOLES OF WATER ARE PRODUCED WHEN 20 MOLES OF PROPANE ARE BURNED IN EXCESS OXYGEN ON A GAS GRILL.

Explanation:

Equation for the reaction:

C3H8 + 5 O2 --------->  4 H2O + 3 CO2 + Heat

The above equation is in the presence of excess oxygen.

In this reaction,

1 mole of propane forms 4 moles of H2O

If 20 moles of propane were to be used, how many moles of water will be produced?

1 mole of propane = 4 moles of water

20 moles of propane = ( 4 * 20 ) moles of water

= 80 moles of water.

So, if 20 moles of propane were burned in excess oxygen, 80 moles of water will be formed. Propane is heavier than air and when properly combusted produces a large amount of heat. It is also non toxic.

6 0
3 years ago
0.20 L of HNO3 is titrated to equivalence using 0.12 L of 0.2 M NaOH. What is the concentration of the HNO3?
AleksandrR [38]

M_{A}V_{A}=M_{B}V_{B}\\(0.20)(M_{A})=(0.12)(0.2)\\M_{A}=\frac{(0.12)(0.2)}{(0.20)}=\boxed{0.12 \text{ M}}

4 0
2 years ago
Other questions:
  • Which of the following would most likely result in an increase in reaction rate? placing the reactants on a hotplate
    10·1 answer
  • Some oxides are given below. (i)Na2O (ii)NO2 (iii) CO2 (iv) MgO a) Which are the basic oxides among these? b) What is the name o
    8·1 answer
  • Akira records the speed of a reaction, first without a catalyst, and then with a catalyst
    10·2 answers
  • Why was the line of best fit method used to determine the experimental value of absolute zero?
    14·1 answer
  • For elements (Br, Ca, Fe, Na, S, Si, and Xe) which of the following term(s) apply?
    15·1 answer
  • Calculate the pH of a solution created by placing 2.0 grams of yttrium hydroxide, Y(OH)3, in 2.0 L of H2O. Ksp for Y(OH)3 is 6.0
    11·1 answer
  • Find the temperature from 150ml cylinder containing 0.75 moles gas at 153kpa.
    15·1 answer
  • 1
    12·1 answer
  • What does the large number in front of<br> the molecule represent?
    6·2 answers
  • Sucrose decomposes to fructose and glucose in acid solution. When ln [sucrose] is
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!