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4 years ago

Please give it a try....I will do Brainliest

Mathematics

1 answer:

NikAS [45]4 years ago

5 0

the answer is

-6y x -6y x -6y = -216y

4y x 4y = 16y

-216y x -16y = -3456 i believe this is right

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If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar

erma4kov [3.2K]

Answer:

$\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

Step-by-step explanation:

Given

5 tuples implies that:

$n = 5$

$(h,i,j,k,m)$ implies that:

$r = 5$

Required

How many 5-tuples of integers $(h, i, j, k,m)$ are there such that $n\ge h\ge i\ge j\ge k\ge m\ge 1$

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed: This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

$^{n}C_r => ^{n + 4}C_5$

$^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}$

$^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}$

Expand the numerator

$^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

<u><em>Solved</em></u>

6 0

3 years ago

76 less than the quotient of an unknown number and five is 116

SIZIF [17.4K]

N
- -76=116
5

If the question gives you another variable, just switch it out with n

8 0

3 years ago

Need help asap! Please and thank you

FromTheMoon [43]

Answer:

1,2,5 No 3,4 Yes

Step-by-step explanation:

x(x^2-5) No

x(x^2-25x) No

x(x^2-25) Yes

x(x+5)(x-5) Yes

x(x-5)^2 No

3 0

3 years ago

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mote1985 [20]

Answer:

red and green

Step-by-step explanation:

Parallel lines are lines in a plane that are always the same distance apart. Parallel lines never intersect.

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3 years ago

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alekssr [168]

Answer:

3384

Step-by-step explanation:

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3 years ago